Answer:
3x³ + x² + x + 1
= 3x³ - 3x² + 4x² - 4x + 5x - 5 + 6
= 3x²(x - 1) + 4x(x - 1) + 5(x - 1) + 6
= (x - 1)(3x² + 4x + 5) + 6
but 3x³ + x² + x + 1 = (x - 1).Q(x) + R
=> Q(x) = 3x² + 4x + 5
R = 6
Answer:
y=3/5x
Step-by-step explanation:
Im pretty sure this is the correct answer
Answer:
The equation of the line is 2 x - y + 5 = 0.
Step-by-step explanation:
Here the given points are A( 1, 7) & B( -3, - 1) -
Equation of a line whose points are given such that
(
) & (
)-
y -
=
( x -
)
i.e. <em> y - 7=
( x- 1)</em>
<em> y - 7 =
( x -1)</em>
<em> y - 7 = 2 ( x - 1) </em>
<em> y - 7 = 2 x - 2</em>
<em> 2 x - y + 5 = 0</em>
Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.
Answer:
-66
Step-by-step explanation:
solve m(-4)
-4^2 -40
-24
solve n(-24)
3(-24) + 6
-66