<u>Solution</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u>
>> -3 (3 - x) = 2x + 5
>> -3 × (3 - x) = 2x + 5
>> -9 + 3x = 2x + 5
>> 3x - 2x = 9 + 5
>> x = 14
<u>Solution</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u>
>> -6 - 9p = 3p
>> -9p - 3p = 6
>> -12p = 6
>> p = -1/2
<u>Solution</u><u> </u><u>3</u><u> </u><u>:</u><u>-</u>
>> -5 (-4 - a) = 3a + 8
>> -5 × (-4 - a) = 3a + 8
>> 20 + 5a = 3a + 8
>> 5a - 3a = 8 - 20
>> 2a = -12
>> a = -12 / 2
>> a = -6
<u>Solution</u><u> </u><u>4</u><u> </u><u>:</u><u>-</u>
>> s - 6 = -5s
>> s + 5s = 6
>> 6s = 6
>> s = 6 / 6
>> s = 1
Answer:
Number of 1-cm cube 24. Volume of solid 24 cm^2
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
Take 4 1/2 and turn it into just halves by multiplying 4•2 and then adding it to one. 9/2 then multiply that by 2 because you need the denominator to be 4 getting 18/4. Then subtract 11/4 you end up getting 9/4. So technically you have 2 pieces but if you want them both to be 11/4 you only have one
Answer:
-i
Step-by-step explanation:
i^0=1
i^1=i
i^2=-1
i^3=-i
i^4=1
This repeats so we want to see how many 4 factors of i there is in i^(23) which is 5 with a remainder of 3.
So i^(23)=i^3=-i.
i^(23)=i^(5*4+3)=(i^4)^5 * (i^3)=(1)^5 * (-i)=1(-i)=-i.