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IgorLugansk [536]
3 years ago
9

How do you figure out your ratios

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
7 0
Hello
To find an equal ratio, you can either multiply or divide each term in the ratio by the same number (but not zero). For example, if we divide both terms in the ratio 3:6 by the number three, then we get the equal ratio, 1:2.
Aliun [14]3 years ago
6 0
What do you mean by this? If you're looking for a simple response, Google is always helpful.
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What is the rate of change according to the table below?
pychu [463]

Answer:

lets make this like a table

x   y

3=21

4=28

5=35

so since y is bigger lets divide that by x

21/3=7

so the rate of change is 7

Hope This Helps!!!

5 0
2 years ago
Gina Chuez has considered starting her own custom greeting card business. With an initial start up cost of $1500, she figures it
Digiron [165]

1.70 - 0.45 = 1.25

1500 ÷ 1.25 = 1200

Gina must sell 1200 cards before she can make a profit

6 0
3 years ago
Which is the function represented by the table?
Paha777 [63]
The function represented by the table is linear function
and pass with (0,0)
so it is in the form
             f(x) = m x
where m is the slope

m = [ f(x₂) - f (x₁) ] / [ x₂ -x₁]
    (4-0)/(1-0) =4
so
   f(x) = 4 x
4 0
3 years ago
Find the quotient:<br> 3)21<br> A. 6<br> B. 7<br> C. 8<br> D. 9
finlep [7]
The answer is B:7!!!!!!!
4 0
3 years ago
HELPPP!!!
spayn [35]

Answer:

  A. see below for a graph

  B. f(x, y) = f(0, 15) = 90 is the maximum point

Step-by-step explanation:

A. See below for a graph. The vertices are those defined by the second inequality, since it is completely enclosed by the first inequality: (0, 0), (0, 15), (10, 0)

__

B. For f(x, y) = 4x +6y, we have ...

  f(0, 0) = 0

  f(0, 15) = 6·15 = 90 . . . . . the maximum point

  f(10, 0) = 4·10 = 40

_____

<em>Comment on evaluating the objective function</em>

I find it convenient to draw the line f(x, y) = 0 on the graph and then visually choose the vertex point that will put that line as far as possible from the origin. Here, the objective function is less steep than the feasible region boundary, so vertices toward the top of the graph will maximize the objective function.

8 0
3 years ago
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