9514 1404 393
Answer:
a) BE = 5; DE = 6; EF = 4
b) ∠EFC ≅ ∠DA.F ≅ ∠BDE or <em>b = e = f = i</em>
Step-by-step explanation:
Each short segment is the same length as the marked one it is parallel to.
E is the midpoint of BC, so BE = EC = 5.
ADEF is a parallelogram, so DE = A.F = 6.
D is the midpoint of AB, so AD = DB = 4. ADEF is a parallelogram, so ...
EF = AD = 4
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As we have noted, AB║EF and DE║A.F, so corresponding angles and alternate interior angles are congruent. <em>b = e = f = i</em>
There's more than one way to do this problem.
Try this: Mult. both 109 and 5 by 2, obtaining 218 and 10.
What is 218 div. by 10? Do this in your head.
Assuming the equation is x^2 + y^2 = 1, then that's a circle, with radius 1, centered on the origin [0,0].
So there are two tangents at x = 0. They are y = 1, and y = -1 (horizontal lines).
There is one tangent at x = 1. It is x = 1 (a vertical line).
There is no tangent at x = 35, because the original equation has no solution at x = 35.
Answer:
i think c. sorry if its wrong
Step-by-step explanation:
Answer:
37/6
Step-by-step explanation:
-23/6 - 7/3
= -23/6 - 14/6 just make both have the same denominator (2x the 3 to make 6 and do same with numerator)
= 37/6 or 6 1/6
