$\Omega=\{1;\ 2;\ 3;\ 4;\ 5;\ 6;\ 7;\ 8;\ 9;\ 10\}\\\\|\Omega|=10\\\\A=\{1;\ 3;\ 6;\ 7\};\ B=\{2;\ 3\}\\\\A\ \cup\ B=\{1;\ 2;\ 3;\ 6;\ 7\}\\\\|A\ \cup\ B|=5\\\\P(A\ \cup\ B)=\dfrac{|A\ \cup\ B|}{|\Omega|}\to P(A\ \cup\ B)=\dfrac{5}{10}=\dfrac{1}{2}=0.5=0.50$

4 0

3 years ago

Read 2 more answers

PLEASE HELP I WOULD LOVE ITTT THANK YOUUU

Trava [24]

Answer:

A function that is one to one

Step-by-step explanation:

Each input has one output.

7 0

2 years ago

Cynthia invests some money in a bank which pays 5% compound interest per year. She wants it to be worth over £8000 at the end of

Agata [3.3K]

$\bf \qquad \textit{Compound Interest Earned Amount}\\\\A=P\left(1+\frac{r}{n}\right)^{nt}\quad \begin{cases}A=\textit{accumulated amount}\to &8000\\P=\textit{original amount deposited}\\r=rate\to 5\%\to \frac{5}{100}\to &0.05\\n=\begin{array}{llll}\textit{times it compounds per year}\\\textit{is only once, so}\end{array}\to &1\\t=years\to &3\end{cases}$

$\bf 8000=P\left(1+\frac{0.05}{1}\right)^{1\cdot 3}\implies 8000=P(1.05)^3\implies \cfrac{8000}{1.05^3}=P\\\\\\6910.70\approx P\implies \stackrel{\textit{rounded up}}{6911 = P}\qquad therefore\qquad 6911~~\leqslant ~~P$

6 0

3 years ago

Solve the percent problem 76 gallons is 126% of ___ gallons. Round to the nearest hundredth, if necessary.

Burka [1]

Answer:

60.32

Step-by-step explanation:

126%=1.26

60.32*1.26=76.0032

76.0032≈76

7 0

2 years ago