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IRINA_888 [86]
3 years ago
11

Solve the equation for X and show your work. 3x= 15

Mathematics
2 answers:
dem82 [27]3 years ago
5 0
X=5

divide both sides by 3

3/3
15/3

5
Aleksandr-060686 [28]3 years ago
3 0

Answer:

5

Step-by-step explanation:

15/3=5

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Jenny invests $8500 for 3 years in a savings account. She gets 2.3% per year compound interest. How much money will Jenny have i
Nesterboy [21]

Answer:$9,100.09

Step-by-step explanation:

3 0
3 years ago
hat is the average rate of change of f(x), represented by the table of values, over the interval [-2, 3]? x f(x) -6 2.5 -2 2.5 0
vodomira [7]
Your table of values is so difficult to read that many of us helpers would just skip your post.

<span>x f(x) -6 2.5 -2 2.5 0 2 2 0 3 5 5 2.5 1 0.5</span>  could be put into far clearer format as follows:

 x   f(x)
--  -----
-6  2.5
-2  2.5
and so on.  Please fix it.

The "average rate of change" formula is 

                  f(x2) - f(x1)
av r of c = ---------------
                     x2-x1

so if you go from (-6, 2.5) to (2.5, 10.5), the av r of c would be
                  
                 10.5 - 2.5            9        18
             ------------------ = -------- = -----
                 2.5-(-6)            8.5         17

This may or may not be your final answer.  Again, please put your data table into readable form and then find the av r of c over the interval [-2,3].
7 0
3 years ago
Which number can be inserted in the box to make the equation below true?
Andrej [43]

Answer:

A. 5

Step-by-step explanation:

3 0
3 years ago
In a class of students, the following data table summarizes how many students have a cat or a dog. What is the probability that
leonid [27]

Given:

Number of students who has a cat and a dog = 5

Number of students who has a cat but do not have a dog = 11

Number of students who has a dog but do not have a cat = 3

Number of students who neither have a cat nor a dog = 2

To find:

The probability that a student has a cat given that they do not have a dog.

Solution:

Let the following events:

A = Student has a cat

B = Do not have a dog

Total number of outcomes is:

5+3+11+2=21

The probability that a student has a cat but do not have a dog is:

P(A\cap B)=\dfrac{11}{21}

The probability that a student do not have a dog is:

P(B)=\dfrac{11+2}{21}

P(B)=\dfrac{13}{21}

The conditional probability is:

P\left(\dfrac{A}{B}\right)=\dfrac{P(A\cap B)}{P(B)}

P\left(\dfrac{A}{B}\right)=\dfrac{\dfrac{11}{21}}{\dfrac{13}{21}}

P\left(\dfrac{A}{B}\right)=\dfrac{11}{13}

Therefore, the probability that a student has a cat given that they do not have a dog is \dfrac{11}{13}.

5 0
3 years ago
Help please!!!
Yuliya22 [10]

Hi there!

Adjacent angles, or angles that are next to each other, add up to 180 degrees. They are supplementary.

Examples: 1 and 4, 3 and 4, 2 and 3, 1 and 1

Opposite angles, or angles that are opposite of each other, have the same measure.

Examples: 1 and 3, 2 and 4

I hope this helps!

8 0
3 years ago
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