Slope (y2-y1)/(x2-x1)
(0-4)/(-5-5) = -4/-10 = 2/5
Y = 2/5x + b
Plug in any point
4 = 2/5(5) + b
4 = 2 + b, b= 2
Final equation: y = 2/5x + 2
Y= hx + ex ) x is the number of days jada has worked
Answer with Step-by-step explanation:
Since we have given that
Initial velocity = 50 ft/sec = 
Initial height of ball = 5 feet = 
a. What type of function models the height (ℎ, in feet) of the ball after tt seconds?
As we know the function for height h with respect to time 't'.

b. Explain what is happening to the height of the ball as it travels over a period of time (in tt seconds).
What function models the height, ℎ (in feet), of the ball over a period of time (in tt seconds)?
if it travels over a period of time then time becomes continuous interval . so it will use integration over a period of time
Our function becomes,

Answer:
the value of y and x are 16times(9xdividedby5)
4y= 4times(9xdividedby5)
Step-by-step explanation:
For this case we must factor
of the following expression:

By law of signs of multiplication it is fulfilled that:

So we have to:

Thus, by factoring we have:

Answer:
