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2 years ago

What amount would u have if u deposited 1800 a year for 30 years at 7% compounded annually

Mathematics

1 answer:

AVprozaik [17]2 years ago

4 0

Answer: $183,731

Step-by-step explanation:

After 30 years, the interest is $183,731

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6x + 4x - 1 = 2(5x + 4)

garik1379 [7]

Answer: no solutions

Step-by-step explanation:

8 0

3 years ago

Carla wants to start a college fund for her daughter Lila. She puts $63,000 into an account that grows at a rate of 2.55% per ye

Oksanka [162]

Answer:

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 63000

r = 2.55% = 2.55/100 = 0.0255

n = 12 because it was compounded 12 times in a year.

Therefore, function, C(t), that represents the amount of money in the account t years after the account is opened is

C(t) = 63000(1 + 0.0255/12)^12t

C(t) = 63000(1.002125)^12t

For C(t) = 100000,

100000 = 63000(1.002125)^12t

100000/63000 = (1.002125)^12t

1.587 = 1.002125)^12t

Taking log of both sides

Log 1.587 = log 1.002125)^12t

Log 1.587 = 12tlog 1.002125)^

0.2005 = 12t × 0.00092

0.2005 = t × 0.01104

t = 0.2005/0.01104

t = 18.16 years

5 0

3 years ago

Round to the place value of the underline 9 in 497,385

skelet666 [1.2K]

Ten thousand is the place value of the 9 in that number

4 0

3 years ago

Read 2 more answers

What is 45% of 8.5 ?

satela [25.4K]

Answer:

3.825

Step-by-step explanation:

First, you have to move the decimal two over on 45%. If you move the decimal over two spaces to the right, it would be 0.45. In math, of means to multiply, so then you multiply 0.45 and 8.5 to get your answer of 3.825.

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =

sveta [45]

Answer:

$\displaystyle n^3-\frac{1}{n^{2}}$

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

$(a^x)^y=(a^y)^x=a^{xy}$

$\displaystyle a^{-x}=\frac{1}{a^x}$

We are given the expression:

$2^m=n$

We need to express the following expression in terms of n.

$8^m-4^{-m}$

It's necessary to modify the expression to use the given equivalence.

Recall $8=2^3 \text{ and }4 = 2^2$ . Thus:

$(2^3)^m-(2^2)^{-m}$

Applying the property:

$(2^m)^3-(2^m)^{-2}$

Substituting the given expression:

$n^3-n^{-2}$

Or, equivalently:

$\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}$

5 0

2 years ago