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1 year ago

Which graph represents the function f(x) = |x + 3|?

Mathematics

2 answers:

Ulleksa [173]1 year ago

8 0

Answer:

second graph

Step-by-step explanation:

DIA [1.3K]1 year ago

5 0

Answer:

Graph of Modulus

The graph of a modulus or absolute value function is in a form of a 'V' shape whose vertex depends upon the coordinates. The equation for the graph is given as,

where,

(a, b) are the coordinates of the vertex of 'v' in the form of (x, y),

And h shows how wider or lean will be the function, for h=0, it is a straight line, while for a negative value the graph will face downwards and opposite for a positive value.

Given to us

y = |x-3|

On the coordinate plane

The graph will be in the shape of a 'V' whose vertex will lay at the coordinates (3, 0). As the value of a is 1 the graph will face upwards. As shown below on the graph.

Learn more about Modulus:

brainly.com/question/18106342

Step-by-step explanation:

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The sides of a triangle are x,x+1,2x-1 and its area is x root 10. Find the value of x

Marianna [84]

You can use Heron's formula to solve this problem.

 $A= \sqrt{s(s-a)(s-b)(s-c)}$ , where A is the area; a,b,с are the sides; s is the semiperimeter of the triangle
 $s= \frac{a+b+c}{2}$

According to conditions:
a = x
b = x+1
с = 2x-1

Calculate the semiperimeter:
 $s= \frac{x+x+1+2x-1}{2} = \frac{4x}{2}=2x$

Now we can compose and solve the equation according to Heron's formula:
 $\sqrt{2x(2x-x)(2x-(x+1))(2x-(2x-1))}=x \sqrt{10} \\ \sqrt{2x(x)(2x-x-1)(2x-2x+1)}=x \sqrt{10} \\ \sqrt{2x^2(x-1)(1)}=x \sqrt{10} \\ \sqrt{2x^3-2x^2}=x \sqrt{10} \ \ \ |()^2 \\ 2x^3-2x^2=10x^2 \\ 2x^3-2x^2-10x^2=0 \\ 2x^3-12x^2=0 \ \ |:2 \\ x^3-6x^2=0 \\ x^2(x-6)=0 \\ \\ x^2=0 \\ x=0 \ \ \ \O \\ or \\ x-6=0 \\ x=6$

As a result, x = 6 is your answer.

I hope this helped.

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2 years ago