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andrew11 [14]
3 years ago
7

FSA Mathematics Practice Test Questions

Mathematics
1 answer:
Luda [366]3 years ago
8 0
There is no number line shown...
Brainliest would be nice
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(x-6)^2+(y+5)^2=212 what is the center of the circle?
madam [21]
The circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r". 
Therefore the center is: (6,-5)
4 0
3 years ago
Use the Law of Cosines to find the missing angle. In triangle JKL, j=3in., k=4in., and l=2.89., find mJ
slega [8]
Using the law of cosine for Triangle KJL, we can write:

j^{2} = k^{2} + l^{2}-2(k)(l)cos(J)  \\  \\ 
2(k)(l)cos(J)=k^{2} + l^{2}- j^{2} \\  \\ 
cos(J)= \frac{k^{2} + l^{2}- j^{2}}{2(k)(l)}

Using the values of k,j and l, we can write:

cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)}  \\  \\ 
cos(J)= 0.664 \\  \\ 
J= cos^{-1}(0.664) \\  \\ 
J=48.39

Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer
8 0
3 years ago
Read 2 more answers
I need help on this question
egoroff_w [7]
25 is the answer hope it helped
8 0
4 years ago
AABC is translated 2 units right and 1 unit down<br> What is the new location of point C?
Igoryamba

The answer is (4, -6), or the fourth option.

4 0
3 years ago
In October, Greg and Thomas had the same amount of money in their savings accounts. In November, Greg deposited $120 into his ac
Leona [35]
Let's give the variable that you are trying to answer for a symbol. Let's call it X.

X = the amount of money both Greg and Thomas had in October

We know that in November, Greg added $120 to his account. So, Greg's account has: X + 120

We know that Thomas increased the money in his account by 20%, so Thomas' account has: X + 0.2X, or 1.2X

We know that these two amounts are equal:
X + 120 = 1.2X

Solve for X:
X + 120 - X = 1.2X - X
120 = .2X
120 / .2 = .2X / .2
600 = X


5 0
4 years ago
Read 2 more answers
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