Answer: a²+b² = -99/2
Step-by-step explanation:
Since we are given two equations, this equations will be solved simultaneously to get a² and b²
a³ - 3ab² = 47 ... 1
b³ - 3a² b = 52... 2
From 1, a(a² - 3b²) = 47...3
From 2, b(b² - 3a²) = 52... 4
Adding 3 and 4, we have;
a²+b²-3b²-3a² = 99 (note that a and b will no longer be part of the equations as they have been factored out)
a²+b²-(3b²+3a²) = 99
(a²+b²) -3(b²+a²)= 99
Taking the difference we have
- 2(a²+b²) = 99
a²+b² = -99/2
Answer:
Mean = 1.42
Variance = 0.58
Step-by-step explanation:
Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.
Also, joint probability function of X and Y are given.
To find:
mean and variance of X
Solution:
From the given joint probability function of X and Y,

Mean of X:

Variance of X:

![var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58](https://tex.z-dn.net/?f=var%28X%29%3DE%5Cleft%20%5B%20X%5E2%20%5Cright%20%5D-%5Cleft%20%28%20E%5Cleft%20%5B%20X%20%5Cright%20%5D%20%5Cright%20%29%5E2%5C%5C%3D%5Cfrac%7B31%7D%7B12%7D-%5Cleft%20%28%20%5Cfrac%7B17%7D%7B12%7D%20%5Cright%20%29%5E2%5C%5C%3D%5Cfrac%7B31%7D%7B12%7D-%5Cfrac%7B289%7D%7B144%7D%5C%5C%3D%5Cfrac%7B372-289%7D%7B144%7D%5C%5C%3D%5Cfrac%7B83%7D%7B144%7D%5C%5C%3D0.58)
En algunos bancos, cuentas de ahorro o incluso en prestamos y empeños podemos observar que se cobra un interés mensual. Esto no significa que todos los intereses deban ser así.
El periodo, es el tiempo en el que se aplica el interés, este puede ser anual, mensual, semanal, o incluso por día.
Answer:
m= 234
Step-by-step explanation:
Answer:
Step-by-step explanation:
- Binomial: 2 terms
- Trinomial: 3 terms
- Linear: a straight line
- Quadratic: like a curved line
(3x + 2) - (x + 5)
1(3x + 2) - 1(x + 5)
3x + 2 - x - 5 <== combine like terms
3x - x + 2 - 5
2x - 3 <== final answer, linear binomial
(2x + 8) + (3x² - 2)
1(2x + 8) + 1(3x² - 2)
2x + 8 + 3x² - 2
3x² + 2x + 6 <== final answer, quadratic trinomial
(3x + 8) + (4x² - x)
1(3x + 8) + 1(4x² - x)
3x + 8 + 4x² - x
4x² + 2x + 8 <== final answer, quadratic trinomial
(x² + 5x minus (-) 2) + (8 minus (-) 5x)
(x² + 5x - 2) + (8 - 5x)
1(x² + 5x - 2) + 1(8 - 5x)
x² + 5x - 2 + 8 - 5x
x² + 6 <== final answer, quadratic binomial
(x² + 7x) - (x² + 5)
1(x² + 7x) - 1(x² + 5)
x² + 7x - x² - 5
7x - 5 <== final answer, linear binomial
Hope this helps!