Answer:
% change in stopping distance = 7.34 %
Step-by-step explanation:
The stooping distance is given by
We will approximate this distance using the relation
dx = 26 - 25 = 1
T' = 2.5 + x
Therefore
This is the stopping distance at x = 25
Put x = 25 in above equation
2.5 × (25) + 0.5× 
+ 2.5 + 25 = 402.5 ft
Stopping distance at x = 25
T(25) = 2.5 × (25) + 0.5 ×
T(25) = 375 ft
Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft
% change in stopping distance = 
× 100
% change in stopping distance = 7.34 %
Answer:
a) 7/4 b) 15/2
Step-by-step explanation:
a) Scale Factor = Image / Object
Take the side of Triangle ABC that's BC Why? Because it corresponds with the Image Triangle ADE's DE
= 21/12 = 7/4
b) 7/4 = 10+ x / 10
Cross Multiply
= 4 ( 10 + x ) = 70
= 40 + 4x = 70
= 4x = 70-40
= 4x = 30
= 4x/4 = 30/4
x = 15/2
Answer:
Step-by-step explanation:
2*4+3= 11/4
2*2+1= 5/2
11/4 * 5/2 = 55/8
Simplified 6 7/8
Answer:
210
Step-by-step explanation:
JQ is 5 times the length of JK
● JQ = 5JK
JK = 42
● JQ = 5 × 42
● JQ = 210
I just need to answer some questions lol
