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vovangra [49]
2 years ago
13

I have a issue in solving this question√24/8 + √54/12​

Mathematics
1 answer:
Paul [167]2 years ago
3 0

\dfrac{\sqrt{24}}{8}+\dfrac{\sqrt{54}}{12}=\dfrac{2\sqrt6}{8}+\dfrac{3\sqrt6}{12}=\dfrac{\sqrt6}{4}+\dfrac{\sqrt6}{4}=\dfrac{2\sqrt6}{4}=\dfrac{\sqrt6}{2}

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A rectangular garden has an area of 46 1/2 square feet. If the garden is 7 1/2 feet long, how many feet wide is it?
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Answer:

The answer is 6 1/5 feet in width.

Step-by-step explanation:

Since the formula for area is <em>wl</em> or <em>width </em>x <em>length</em>, we can utilize our reversive property to find our width by dividing the Area we are given by our length, giving us the missing width in return. Dividing 46.5 square feet by 7.5 feet gives us 6.2 feet, or 6 1/5 feet.

Hope this helps!

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stira [4]
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How do you solve algebra special systems
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After that, use substitution (Plug -X-3 in place of Y in X+Y=4)

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Read 2 more answers
What is the vertex form of the quadratic equation represented on the table?
sergeinik [125]

Check the picture below, so the parabola looks more or less like so, hmmm with a vertex at (-1 , -4), so, using those values from the table

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{vertex}{\stackrel{h}{-1}~~,~~\stackrel{k}{-4}}\qquad \implies y=a[x-(-1)]^2-4\implies y=a(x+1)^2-4 \\\\\\ \textit{we also know that} \begin{cases} x=2\\ y=14 \end{cases}\implies 14=a(2+1)^2-4\implies 18=9a \\\\\\ \cfrac{18}{9}=a\implies 2=a~\hspace{10em}\boxed{y=2(x+1)^2-4}

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2 years ago
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