Answer is: C
√11 ≈ 3.3661
Which the closest to your answers is 3.3
Answer:
A. EG = √3 × FG
D. EG = √3/2 × EF
E. EF = 2 × FG
Step-by-step explanation:
∵ tan 60 = √3
∵ tan60 = EG/GF
∴ EG/GF = √3
∴ EG = √3 × GF ⇒ A
∵ m∠F = 60°
∵ sin60 = √3/2
∵ sin 60 = EG/EF
∴ √3/2 = EG/EF
∴ EG = √3/2 × EF ⇒ D
∵ cos60 = 1/2
∵ cos60 = GF/EF
∴ GF/EF = 1/2
∴ EF = 2 × GF ⇒ E
3*2=6
6-x-2=0
4=x
The answer is 4
Answer:
15.5 ft
Step-by-step explanation:
The geometry of the problem can be modeled by a right triangle with hypotenuse 16 ft and one side length of 4 ft. If x represents the height of the ladder on the building, then the Pythagorean theorem tells us ...
x^2 + (4 ft)^2 = (16 ft)^2
x^2 = 240 ft^2 . . . . . . subtract 16 ft^2
x ≈ 15.5 ft . . . . . . . . . . take the square root
The top of the ladder is about 15.5 ft above the ground.
60 divided by 5 is 12 so it would take him 12 minutes to complete the line
