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slavikrds [6]
2 years ago
10

What is the 95% confidence interval of E(Y) at X = 4?

Mathematics
1 answer:
diamong [38]2 years ago
4 0

Based on the calculations, the 95% confidence interval of E(Y) is equal to 52.3% ± 3.26%.

<h3>How to construct a 95​% confidence interval?</h3>

Mathematically, a confidence interval of 95% is given by;

α = 1 - 0.95

α = 0.05.

α/2 = 0.05/2 = 0.025.

Next, we would determine the standard deviation of the mean:

Standard deviation of mean = 50/√800

Standard deviation of mean = 1.77.

From the z-table, the z-score of a 95% confidence interval is equal to 1.96.

Confidence interval (0.05, 50, 800) = 1.77 × 1.96

Confidence interval (0.05, 50, 800) = 3.46.

Mathematically, the confidence interval for a mean is given by:

Mean ± (t-critical × (standard deviation/√(sample size)))

Confidence interval = 52.3% ± 3.26%.

Read more on confidence interval here: brainly.com/question/25779324

#SPJ1

<u>Complete Question:</u>

A research team studied Y, the percentage of voters in favor of a candidate. The random variable Y had standard deviation o = 50%. A random sample of 800 voters was selected, and their average was y-bar(800) = 52.3%. What is the 95% confidence interval for E(Y)?

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The function h(x) is given below:
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Step-by-step explanation:

The domain and range of a function and its inverse are inverted i.e. The domain of the function will become range of its inverse and the range of the function will become the domain of its inverse.

When representing the function in ordered pairs, the first values in the pair represents the domain and second values represent the range of the function.

h(x) = {3,5),(5,-7)(6,-9)(10,-12)(12,16)}

Domain of h(x) is: {3, 5, 6, 10, 12}

Range of h(x) is: (5, -7, -9, -12, 16}

So,

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Emily loves potato chips and buys a bag every 5 days. Each bag costs $2.50, including tax. Once each month, she also treats hers
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The number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. A sample of 1
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Answer:

The 98% confidence interval for the population mean number of hours worked per year per person is (2146, 2193).

Step-by-step explanation:

The question is incomplete.

The number of hours registered in the sample are:

2051 2061 2162 2167 2169 2171

2180 2183 2186 2195 2196 2198

2205 2210 2211

The sample mean can be calculated as:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{15}(2051+2061+2162+2167+2169+2171+2180+2183+2186+2195+2196+2198+2205+2210+2211)\\\\\\M=\dfrac{32545}{15}\\\\\\M=2169.67\\\\\\

We have to calculate a 98% confidence interval for the mean.

The population standard deviation is know and is σ=39.

The sample mean is M=2169.67.

The sample size is N=15.

As σ is known, the standard error of the mean (σM) is calculated as:

\sigma_M=\dfrac{\sigma}{\sqrt{N}}=\dfrac{39}{\sqrt{15}}=\dfrac{39}{3.873}=10.07

The z-value for a 98% confidence interval is z=2.326.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=2.326 \cdot 10.07=23.43

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 2169.67-23.43=2146\\\\UL=M+t \cdot s_M = 2169.67+23.43=2193

The 98% confidence interval for the population mean is (2146, 2193).

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