Answer:
The equation i.e. used to denote the population after x years is:
P(x) = 490(1 + 0.200 to the power of x
Step-by-step explanation:
This problem could be modeled with the help of a exponential function.
The exponential function is given by:
P(x) = ab to the power of x
where a is the initial value.
and b=1+r where r is the rate of increase or decrease.
Here the initial population of the animals are given by: 490
i.e. a=490
Also, the rate of increase is: 20%
i.e. r=20%
i.e. r=0.20
Hence, the population function i.e. the population of the animals after x years is:
P(x) = 490(1 + 0.200 to the power of x
Answer:
<h2><em>29.4 length and 21.4 width.</em></h2>
Step-by-step explanation:
To fin the dimensions of the pool we need to use the total area of the pool plus the concrete walkway. Lets say that <em>W </em>is the width and <em>L </em>the length. We know that, the walkway has 3 ft wide, this means that the width and length are increased by 6ft (3ft on each side). So, the total area can be expressed like this:
.
In addition, we know that the total area is 970 and the length is 8 ft longer than the width (
). So:

With this quadratic equation we're gonna have to solution, the most reasonable is part of the answer. So, solving the equation we have as solutions:
and
Therefore, the width is 21.4 ft, because the negative number cannot represent distances.
Using the relation between length and width:

<em>Therefore, the dimensions of the pool are 29.4 length and 21.4 width.</em>
If the annual rate in 10 years has the same quadralaterical value the answer would be 47.9 but we can make sure our answer is correct
what we know:
The cost changed in 10 years to 23.95
if the cost changed another 10 years it would be another 23.95, 23.95+23.95=47.9 Which is our answer pls mark brainliest
(x1, y1) (x2, y2)
(-4, 5) (-1, 1)
x2-x1
-1 - -4
-1+4
3
y2-y1
1- -4
1+4
5
answer : (3,5)
I believe this is right, hope this helps!
Answer:
72. 5
73. -5
74.r =2.40753645…,−2.90753645
75. v =1.53066238…,−0.13066238
Step-by-step explanation: