Answer / Explanation:
195.200.0.0/16
Note: Class C address can not be assigned a subnet mask of /16 because class c address has 24 bits assigned for network part.
2ⁿ = number of subnets
where n is additional bits borrowed from the host portion.
2ˣ - 2 = number of hosts
where x represent bits for the host portion.
Assuming we have 195.200.0.0/25
In the last octet, we have one bit for the network
number of subnets = 2¹ =2 network addresses
number of host = 2⁷ - 2= 126 network addresses per subnets
Answer:
The correct answer to this question is given below in the explanation section.
Explanation:
The correct answer to this question is : 4.
When you run this program in Java. The output produce by this program is 4
The given code is:
import java.util.ArrayList;
public class arrayList7
{
public static void main(String[] args) {
ArrayList one = new ArrayList ();
Integer count=3;
count=count+1;
one.add(2);
one.add(count);
System.out.println(one.get(1));
}
}
This code store the value in ArrayList one variable. It first adds 2 at zero indexes and 4 at first index. When you print the value at index one, you will get the output 4. because the count variable contains 4. If you want to print 2, then you specify the print statement that prints the value at index zero. eg.
System.out.println(one.get(0));
Answer:
The source code has been attached to this response. It contains comments explaining each line of the code. Kindly go through the comments.
To run this program, ensure that the file is saved as ArithmeticProcessor.java
Keep editing line 7 of the code to test for other inputs and arithmetic operation.
A sample output has also been attached to this response.
