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Marianna [84]
3 years ago
9

Which hypervisor works on older pcs without hardware virtualization support?

Computers and Technology
2 answers:
Trava [24]3 years ago
7 0
It is called Virtual Box. VirtualBox has a to a great degree secluded plan with very much characterized inside programming interfaces and a customer/server outline. This makes it simple to control it from a few interfaces without a moment's delay: for instance, you can begin a virtual machine in a regular virtual machine GUI and after that control that machine from the charge line, or potentially remotely.
patriot [66]3 years ago
5 0
The hypervisor which works on older PC's without hardware virtualization support is called VirtualBox. It is a software allows you to run operating systems in special environment which is called virtual machine. It means that you can run another OS without re-installing existing one.
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A continuous and differentiable function f(x) with the following properties: f(x) is decreasing at x=−5 f(x) has a local minimum
butalik [34]

The continuous and differentiable function where f(x) is decreasing at x = −5 f(x) has a local minimum at x = −2 f(x) has a local maximum at x = 2 is given as: y = 9x - (1/3)x³ + 3.

<h3>What is a continuous and differentiable function?</h3>

The continuous function differs from the differentiable function in that the curve obtained is a single unbroken curve in the continuous function.

In contrast, if a function has a derivative, it is said to be differentiable.

<h3>What is the solution to the problem above?</h3>

It is important to note that a function is differentiable when x is set to a if the function is continuous when x = a.

Given the parameters, we state that

f'(5) < 0; and

x = -5

The local minimum is given as:
x = -3;

the local maximum is given as

x = 3

Thus, x = -3 ; alternatively,

x = 3.  With this scenario, we can equate both to zero.

Hence,

x + 3 = 0;

3-x = 0.

To get y' we must multiply both equations to get:

y' = (3-x)(x + 3)

y'   = 3x + 9 - x² - 3x

Collect like terms to derive:

y' = 3x - 3x + 9 - x²; thus

y' = 9-x²

When y' is integrated, the result is

y = 9x - (x³/3) + c

Recall that

F (-5) < 0

This means that:

9 x -5 - (-5³/3) + c < 0
⇒ -45 + 125/3 + c <0
⇒ -10/3 + c < 0

Collecting like terms we have:
c < 10/3; and

c < 3.33


Substituting C into

f(x) = 9x - x³/3 + c; we have

f(x) = 9x - x³/3 + 3, which is the same as  y = 9x - (1/3)x³ + 3.

Learn more about differentiable functions at:
brainly.com/question/15047295
#SPJ1

7 0
2 years ago
Switched backbone networks:_____.a. always use a ring topology.b. require much more management that do routed backbone networks.
Gre4nikov [31]

Answer:

c

Explanation:

spongo  

7 0
3 years ago
This has nothing to do with anything school related, but I'm new to car audio and I was wondering, what happens or what would ha
DerKrebs [107]
It most likely can but It may damage your system. So you should seek out professional help from a car dealership and do more research.

Hope this helps.<span />
7 0
3 years ago
Given a class called Measure that has the methods and data as specified, choose the correct code to satisfy the requirements of
Nina [5.8K]

Answer:

D

Explanation:

7 0
3 years ago
Suppose that a disk drive has 5,000 cylinders, numbered 0 to 4,999. The drive is currently serving a request at cylinder 2,150,
Zina [86]

Answer:

The queue pending requests of FIFO order is ;

86, 1470, 1774, 948, 1509, 1022, 1750, 130.

Explanation:

The FCFS schedule is 143, 86, 1470, 913, 1774, 948, 1509, 1022, 1750, 130.

Total seek distance is 7081.

The SSTF schedule is 143, 130, 86, 913, 948, 1022, 1470, 1509, 1750, 1774.

Total seek distance is 1745.

The LOOK schedule is 143, 913, 948, 1022, 1470, 1509, 1750, 1774, 130, 86.

Total seek distance is 3319.

The SCAN schedule is 143, 913, 948, 1022, 1470, 1509, 1750, 1774, 4999, 130, 86.

Total seek distance is 9769.

7 0
3 years ago
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