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2 years ago

Can someone help me please

Mathematics

1 answer:

grandymaker [24]2 years ago

3 0

Answer:

D. f(x) = 2x³ - 6x² - 2x + 6

Step-by-step explanation:

From the graph :

A(0 ,6) and B(1 , 0) are two points of the graph.

Then

Their coordinates must verify its equation.

The only equation that verifies those coordinates is :

f(x) = 2x³ - 6x² - 2x + 6

because :

• f(0) = 2(0)³ - 6(0)² - 2(0) + 6 = 6

• f(1) = 2(1)³ - 6(1)² - 2(1) + 6 = 2 - 6 - 2 + 6 = 0

therefore

The equation of the function of the line is :

f(x) = 2x³ - 6x² - 2x + 6

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3 years ago

Is x = 1 a function?

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4 years ago

lysha is at a local library with her best friend. they've noticed a lot of cute boys in the library, and alysha bets that of the

Annette [7]

Using the binomial distribution, there is a 0.1201 = 12.01% probability that Alysha will win the bet.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

For this problem, the parameters are given as follows:

n = 20, p = 0.5.

She wins the bet if there are 12 boys, hence the probability is P(X = 12), found as follows:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{20,12}.(0.5)^{12}.(0.5)^{8} = 0.1201$

0.1201 = 12.01% probability that Alysha will win the bet.

More can be learned about the binomial distribution at brainly.com/question/24863377

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1 year ago

What's 2sin(2theta)=1? Need it for webassign.

lutik1710 [3]

<em>Solve: </em> $2sin(2x) = 1$

Divide both sides by 2.
$sin(2x) = \frac{1}{2}$

Take the sine inverse of both sides:
$2x = sin^{-1}(\frac{1}{2})$
$2x = \frac{\pi}{6}, \frac{5\pi}{6}, 0 \leq x \leq 2\pi$
$x = \frac{\pi}{12}, \frac{5\pi}{12}$

But we know there are more solutions if we extend the domain. In fact, there are infinitely more solutions since the domain of sine is all real x values.
Thus, we can develop a general solution:

For every $\pi$ units, there is another solution for both $\frac{\pi}{12}$ and $\frac{5\pi}{12}$

General solutions:
$x = \pi n + \frac{\pi}{12}, n \in \mathbb{Z}$
$x = \pi n + \frac{5\pi}{12}, n \in \mathbb{Z}$

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3 years ago