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ella [17]
2 years ago
11

Can someone help me please

Mathematics
1 answer:
grandymaker [24]2 years ago
3 0

Answer:

D. f(x) = 2x³ - 6x² - 2x + 6

Step-by-step explanation:

From the graph :

A(0 ,6) and B(1 , 0) are two points of the graph.

Then

Their coordinates must verify its equation.

The only equation that verifies those coordinates is :

f(x) = 2x³ - 6x² - 2x + 6

because :

• f(0) = 2(0)³ - 6(0)² - 2(0) + 6 = 6

• f(1) = 2(1)³ - 6(1)² - 2(1) + 6 = 2 - 6 - 2 + 6 = 0

therefore

The equation of the function of the line is :

f(x) = 2x³ - 6x² - 2x + 6

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5 0
3 years ago
Read 2 more answers
Find an equation of the circle that has center (-4,3) and passes through (6,-4).
kumpel [21]

Answer:

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Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center of the circle and r is the radius of the circle.

Given that (h,k)\rightarrow(-4,3) and it passes (6,-4), their distance between each other must the radius of the circle, so we can use the distance formula to find the radius:

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Therefore, if the length of the radius is r=\sqrt{149} units, then r^2=149, making the final equation of the circle (x+4)^2+(y-3)^2=149

5 0
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