The function f(x) is represented by this table of values. x f(x) -5 35 -4 24 -3 15 -2 8 -1 3 0 0 1 -1 Match the average rates of
change of f(x) to the corresponding intervals. Tiles -3 -8 -7 -4 Pairs [-5, -1] [-4, -1] [-3, 1] [-2, 1]
1 answer:
The given data is shown in the table below.
x: -5 -4 -3 -2 -1 0 1
f(x): 35 24 15 8 3 0 -1
A graph of the data is shown below.
Calculate rates of change, r.
Interval: [-5, -1]
r = (35 - 3)/(-5+1) = -8 (tile -8)
Interval: [-4, -1]:
r = (24 - 3)/(-4 + 1) = -7 (tile -7)
Interval: [-3, 1]:
r = (15 + 1)/(-3 - 1) = -4 (tile - 4)
Interval: [-2, 1]
r = (8 + 1)/(-2 - 1) = -3 (tile -3)
Answer:
Tile Interval
----- ----------
-3 [-2, 1]
-4 [-3, 1]
-7 [-4, -1]
-8 [-5, -1]
x: -5 -4 -3 -2 -1 0 1
f(x): 35 24 15 8 3 0 -1
A graph of the data is shown below.
Calculate rates of change, r.
Interval: [-5, -1]
r = (35 - 3)/(-5+1) = -8 (tile -8)
Interval: [-4, -1]:
r = (24 - 3)/(-4 + 1) = -7 (tile -7)
Interval: [-3, 1]:
r = (15 + 1)/(-3 - 1) = -4 (tile - 4)
Interval: [-2, 1]
r = (8 + 1)/(-2 - 1) = -3 (tile -3)
Answer:
Tile Interval
----- ----------
-3 [-2, 1]
-4 [-3, 1]
-7 [-4, -1]
-8 [-5, -1]
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Answer:
The roots of equations are as m = And n =
Step-by-step explanation:
The given quadratic equation is 2 x² + 6 x - 1 = 0
This equation is in form of a x² + b x + c = 0
Let the roots of the equation are ( m , n )
Now , sum of roots =
And products of roots =
So, m + n = = - 3
And m × n =
Or, (m - n)² = (m + n)² - 4mn
Or, (m - n)² = (-3)² - 4 ()
Or, (m - n)² = 9 + 2 = 11
I.e m - n =
Again m + n = - 3 And m - n =
Solving this two equation
(m + n) + ( m - n) = - 3 +
I.e 2 m = - 3 +
Or, m =
Similarly n =
Hence the roots of equations are as m = And n =
Answer