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2 years ago

A piecewise function is shown here:

Mathematics

1 answer:

prohojiy [21]2 years ago

6 0

f(0) = -3(0) + 5 = 5

f(-4) = -3(-4) + 5 = 17

f(6) = ½(6) - 4 = -1

f(9) = 2

f(2) = ½(2) - 4 = -3

Using the restraints, find which equation the f(x) function validates and plug it in.

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Suppose that you believe that contractor 1 is twice as likely to win as contractor 3 and that contractor 2 is three times as lik

Ray Of Light [21]

Answer:

probability that contractor 1,2 and 3 win is 33%,50% and 17% respectively

Step-by-step explanation:

assuming that there are no other contractors then:

probability that 1 , 2 or 3 win = 1

denoting as X= probability that contractor 3 wins , then assuming that only one wins , we have

probability that 1 , 2 or 3 win = 1

probability that contractor 1 wins + probability that contractor 2 wins + probability that contractor 3 wins = 1

2*P(X) + 3*P(X) + P(X) = 1

6*P(X) = 1

P(X) =1/6

then

-probability that contractor 1 wins = 2/6 (33%)

-probability that contractor 3 wins = 3/6 (50%)

-probability that contractor 3 wins = 1/6 (17%)

3 0

3 years ago

7 + 2X = 5 3 ..... zzzzzzzz

Alex787 [66]

Answer:

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

Three workers have to do a certain job. The first worker can finish the job in 8 hours. The second worker can finish the job in

mestny [16]

Working together three workers would take 1 hour 36 minutes to finish the job

Solution:

Given that first worker can finish the job in 8 hours

So in one hour, first worker can do $\frac{1}{8}$ th of the work

The second worker can finish the job in 4 hours

So in one hour, second worker can do $\frac{1}{4}$ th of the work

The third worker can also finish the job in 4 hours

So in one hour, third worker can do $\frac{1}{4}$ th of the work

The three workers working together in 1 hour can do:

$\frac{1}{8} + \frac{1}{4} + \frac{1}{4} = \frac{1 + 2 + 2}{8} = \frac{5}{8}$

The three worker can thus do $\frac{5}{8}$ th of the work in one hour

Hence the three of them together can finish the work in $\frac{8}{5}$ hours

$\frac{8}{5} = 1\frac{3}{5}$ hours

Thus working together three workers would take 1 hour 36 minutes to finish the job

8 0

3 years ago

Name a plane parallel to DBF.

cestrela7 [59]

Answer:

C.CAE

because those two planes never touch

5 0

3 years ago

Arrange the entries of matrix AB in increasing order of their values. Okay

zubka84 [21]

Answer:

C₂₃ = -186

${}$ ↓

C₁₃ = -32

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C₃₁ = 6

${}$ ↓

C₁₁ = 27

${}$ ↓

C₂₁ = 28

${}$ ↓

C₃₃ = 38

${}$ ↓

C₂₂ = 56

${}$ ↓

C₃₂ = 90

${}$ ↓

C₁₂ = 115

Step-by-step explanation:

The given matrices are;

$A = \left[\begin{array}{ccc}1&7&-1\\5&-2&-9\\-3&8&3\end{array}\right]$ $B = \left[\begin{array}{ccc}5&1&7\\3&15&-2\\-1&-9&25\end{array}\right]$

The cross product of the matrices is found as follows;

$A \cdot B = \left[\begin{array}{ccc}1&7&-1\\5&-2&-9\\-3&8&3\end{array}\right] \times \left[\begin{array}{ccc}5&1&7\\3&15&-2\\-1&-9&25\end{array}\right]$

C₁₁ = 1×5 + 7×3 + (-1) × (-1) = 27

C₁₂ = 1×1 + 7×15 + (-1)×(-9) = 115

C₁₃ = 1×7 + 7×(-2) + (-1)×25 = -32

C₂₁ = 5×5 + (-2)×3 + (-9) × (-1) = 28

C₂₂ = 5×1 + (-2)×15 + (-9)×(-9) = 56

C₂₃ = 5×7 + (-2)×(-2) + (-9)×25 = -186

C₃₁ = (-3)×5 + 8×3 + 3 × (-1) = 6

C₃₂ = (-3)×1 + 8×15 + 3×(-9) = 90

C₃₃ = (-3)×7 + 8×(-2) + 3×25 = 38

Therefore, we get;

$A \cdot B = \left[\begin{array}{ccc}1&7&-1\\5&-2&-9\\-3&8&3\end{array}\right] \times \left[\begin{array}{ccc}5&1&7\\3&15&-2\\-1&-9&25\end{array}\right] = \left[\begin{array}{ccc}27&115&-32\\28&56&-186\\6&90&38\end{array}\right]$

In increasing order, we have;

C₂₃ = -186

${}$ ↓

C₁₃ = -32

${}$ ↓

C₃₁ = 6

${}$ ↓

C₁₁ = 27

${}$ ↓

C₂₁ = 28

${}$ ↓

C₃₃ = 38

${}$ ↓

C₂₂ = 56

${}$ ↓

C₃₂ = 90

${}$ ↓

C₁₂ = 115

7 0

2 years ago