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MArishka [77]
3 years ago
8

Sofia pays $12 for a haircut. Four months later, the price increases to $15.

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
7 0
C.





Because it is so that’s the answer
vitfil [10]3 years ago
4 0

Answer:

C

Step-by-step explanation:

                     .

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Which solution set is graphed on the number line?
sashaice [31]

Answer:

Step-by-step explanation:

an open circle means it contains no equal signs.....everything to the left is shaded....means it is less then

x <  1 (thats a less then sign only) ....no equal sign in there

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3 years ago
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Solve the following system of equations using substitution <br> x = 4 <br> 2x + 4y = 36
DiKsa [7]
Just plug in 4 for the x

2*4 +4y =36
8+4y =36
4y =36-8
4y=28
y= 28/4
y=7
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2 years ago
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Good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.
Tanzania [10]

Tyler concludes that 5x² will always have a larger output for the same value of x.

<u>Look at the graph below and the table given</u>

Take a random value: x = 0

  • When 5x², y = 0
  • When 2^x, y = 1

Here, 1 > 0, making 2^x > 5x²

Hence, 2^x is greater than 5x² at this point. making Tyler's point not applicable.

Disagree with Tyler's point.

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What is the quotient <br> 13632 divided by 48
Brilliant_brown [7]

Answer:

284 is the answer

7 0
3 years ago
A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by ℎ = −16푡 ଶ+103푡+5 w
Liono4ka [1.6K]

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds.  Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

t = 5.0625

Step-by-step explanation:

Given

h(t)=-16t^2+80t+5

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

0=-16t^2+80t+5

Reorder

-16t^2+80t+5 = 0

Using quadratic formula, we have:

t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

Where

a = -16      b =80      c = 5

So, we have:

t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}

t = \frac{-80\±\sqrt{6400 +320}}{-32}

t = \frac{-80\±\sqrt{6720}}{-32}

t = \frac{-80\±82.0}{-32}

This gives:

t = \frac{-80+82.0}{-32} or t = \frac{-80-82.0}{-32}

t = \frac{2}{-32} or t = \frac{-162}{-32}

t = -\frac{2}{32} or t = \frac{162}{32}

But time can not be negative.

So, we have:

t = \frac{162}{32}

t = 5.0625

<em>Hence, time to hit the ground is 5.0625 seconds</em>

3 0
3 years ago
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