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3 years ago

What is the length of the hypotenuse of a right triangle with legs of length 6 and 4 ?

Mathematics

1 answer:

liberstina [14]3 years ago

6 0

Answer:

6²+4²=h²

36+16=h²

$\sqrt{52} = h \: \: \: \: \: \\ hyphotenuse \: is \: 2 \sqrt{13 \:} \\ or \: 7.2111$

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Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at 3 formulas:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

Applying formula (1):

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

Applying formula (2):

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

8 0

2 years ago

Its just a line ;) ___________________

Andrei [34K]

Answer:

I need points

Step-by-step explanation:

hhhccchhxjcjc

4 0

2 years ago

What is the slope of the line that passes through the points (-9, -8)((−15,−16)? Write your answer in simplest form.

alexandr402 [8]

Answer:

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

$Slope=\dfrac{4}{3}$

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -9 ,-8)

point B( x₂ , y₂ )≡ (-15 ,-16)

To Find:

Slope = ?

Solution:

Slope of Line Segment AB is given as

$Slope(AB)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Substituting the values we get

$Slope(AB)=\dfrac{-16-(-8)}{-15-(-9)}\\\\Slope(AB)=\dfrac{-16+8}{-15+9}\\\\Slope(AB)=\dfrac{-8}{-6}=\dfrac{4}{3}$

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

$Slope(AB)=\dfrac{4}{3}$

4 0

3 years ago

Which of the equations below has a slope of 1/4

kenny6666 [7]

Answer:

uh you didnt put the picture please put the picture i really want to help you:)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is the solution to the equation below? Enter the answer in the format p=#, keep your answer as a fraction if necessary. -2/

Scorpion4ik [409]

Let's solve your equation step-by-step.

-2/3p+ 1/6= 7/10

Answer:

p= -4/5

6 0

2 years ago