Determine whether the function f(x)= 1/x^2 is even, odd or neither.
1 answer:
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Answer:
P(x) =x² + 3x + 2
Step-by-step explanation:
You have two zeros, so the polynomial is a quadratic.
The general form of a quadratic is
P(x) = ax² + bx + c
Sum of zeros = -b
Product of zeros = c
The polynomial becomes
P(x) = x² - (sum of zeros)x + (product of zeros)
Sum of zeros = -3 and product of zeros = 2, so
P(x) = x² + 3x + 2
The graph of P(x) (below) shows that the zeros are at -2 and -1
Sum of zeros = -2 + (-1) = -3
Product of zeros = -2 × (-1) = 2
