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LUCKY_DIMON [66]
2 years ago
9

Assuming that boy and girl babies are equally likely, what would be Kathy's probability of having at most one daughter if she

Mathematics
1 answer:
JulijaS [17]2 years ago
4 0

Answer: 0.3125.

Step-by-step explanation:

  • The chance of having a boy is 0.5,
  • the chance of having a girl is also 0.5.

<u>Outcome 1: all boys</u>

boy  boy  boy  boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

<u>Outcome 2: first child is a girl, all others are boys</u>

girl   boy   boy   boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

<u>Outcome 3: second child is a girl, all others are boys</u>

boy   girl   boy   boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

<u>Outcome 4: third child is a girl, all others are boys</u>

boy   boy   girl   boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

<u>Outcome 5: fourth child is a girl, all others are boys</u>

boy   boy   boy   girl

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

Therefore,

0.0625 + 0.0625 + 0.0625 + 0.0625 + 0.0625 = 0.0625 * 5 = 0.3125

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80 minus 58 times 90 times 35 times 12455680
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Now we we will try to apply that formula for a=99/100 and b=100/99.

First rewrite (99/100)^{101}=(99/100)\times (99/100)^{100}

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