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1 year ago

Assuming that boy and girl babies are equally likely, what would be Kathy's probability of having at most one daughter if she

Mathematics

1 answer:

JulijaS [17]1 year ago

4 0

Answer: 0.3125.

Step-by-step explanation:

The chance of having a boy is 0.5,
the chance of having a girl is also 0.5.

Outcome 1: all boys

boy boy boy boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

Outcome 2: first child is a girl, all others are boys

girl boy boy boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

Outcome 3: second child is a girl, all others are boys

boy girl boy boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

Outcome 4: third child is a girl, all others are boys

boy boy girl boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

Outcome 5: fourth child is a girl, all others are boys

boy boy boy girl

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

Therefore,

0.0625 + 0.0625 + 0.0625 + 0.0625 + 0.0625 = 0.0625 * 5 = 0.3125

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Find the value of x for which l is parallel to m.

lozanna [386]

I think its the same on both sides so it would be 154 hope this helps and is right have a nice day

8 0

2 years ago

| 2p -1 | =45, what are the values of p?

Alex73 [517]

Answer:

p = 23 and p = -22

Step-by-step explanation:

| 2p -1 | =45

Absolute value equations have 2 solutions, one positive value and one negative

2p-1 = 45 and 2p-1 = -45

Add 1 to all sides

2p-1+1 = 45+1 and 2p-1+1 = -45+1

2p = 46 2p = -44

Divide by 2

2p/2 = 46/2 and 2p/2 = -44/2

p = 23 and p = -22

5 0

2 years ago

Read 2 more answers

the perimeter of a rectangle is 60 inches. if the length is 4 more than 3 times the width, what is the length and width of the r

Mars2501 [29]

Width = x
length = 3x + 4

x + x + 3x + 4 + 3x + 4 = 60
add
8x + 8 = 60
subtract
8x = 52
x = 6.5

width = 6.5
length = 23.5

4 0

2 years ago

Calcula la longitud en YARDAS de

tatiyna

Answer:

Las longitudes solicitadas en yardas son:

Trayecto A = 109.361 yardas.
Trayecto B = 20.231785 yardas.

Step-by-step explanation:

Para hacer la conversión de unidades que requieres en el ejercicio, debes saber que:

1 metro = 1.09361 yardas

Con ese factor de conversión tú puedes hacer reglas de tres para calcular las medidas que requieres. En el caso del trayecto A:

Si:

1 metro = 1.09361 yardas
100 metros = X

Entonces:

$x=\frac{100m *1.09361yardas}{1m}$

Cancelamos metros y obtenemos:

x = 100 * 1.09361 yardas
x = 109.361 yardas

En este caso, el trayecto A en yardas corresponde a 109.361 yardas. El mismo procedimiento puede aplicarse para el trayecto B:

Si:

1 metro = 1.09361 yardas
18.50 metros = X

Entonces:

$x = \frac{18.50m*1.09361yardas}{1m}$

Cuando se cancelan los metros se obtiene:

x = 18.50 * 1.09361 yardas
x = 20.231785 yardas

Así, el trayecto B en yardas corresponde a 20.231785 yardas.

4 0

2 years ago

Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)

Monica [59]

Answer:

$\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}$

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices $\mathsf{A(x_A, y_A)}$ , $\mathsf{B(x_B, y_B)}$ and $\mathsf{C(x_C, y_C)}$ , have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of analytical geometry is given by the determinant of the vertices divided by two, mathematically,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} \mathsf{x_A} & \mathsf{y_A }& 1 \\ \mathsf{x_B} & \mathsf{ y_B} & 1 \\ \mathsf{ x_C} & \mathsf{ y_C} & 1 \end{array} \right|}{2}$

So, applying this knowledge we're going to have,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2 & -3 & 1 \end{array} \right|}{2}$

$\mathsf{A} \triangle = \dfrac{1}{2}\left[ \left.\begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2& -3 & 1 \end{array} \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]$

$\mathsf{A} \triangle = \dfrac{12 + 14 - 18 - (-8 - 9 - 42)}{2}$

$\red{\mathsf{A} \triangle = \dfrac{67}{2} = 33,5u.a}$

Hope you enjoy it, see ya!)

$\green{\mathsf{FROM}}:$ Mozambique, Maputo – Matola City – T-3

DavidJunior17

3 0

3 years ago