Answer:
yes because it passes the verticle line test.
<span>S = 2πRh + 2πR2
S -2πR2= 2πRh
(S -2πR2) / (2πR) = h</span>
Answer:
Step-by-step explanation:
This can be simplified into

which is saying that you are taking the cubed root of each of those bases. The cubed root of 8 comes out evenly, to 2 (since 2*2*2 = 8). The cubed root of 320 is not so simple. To find it, find the complete factorization of 320. 320 factors to: 5 * 2*2*2*2*2*2 or
![\sqrt[3]{320}= \sqrt[3]{5*2^6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B320%7D%3D%20%5Csqrt%5B3%5D%7B5%2A2%5E6%7D)
Split that 2^6 up into increments of 3's to make the simplifying a bit easier:
![\sqrt[3]{5*2^3*2^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%2A2%5E3%2A2%5E3%7D)
Because the index (the little number sitting in the bend of the radial sign) matches the power on both the 2's we can pull both the 2's out front, leaving:
![4\sqrt[3]{5}](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B5%7D)
but don't forget that we already found that the cubed root of 8 was 2, so multiply that 2 by the 4 to get:
![8\sqrt[3]{5}](https://tex.z-dn.net/?f=8%5Csqrt%5B3%5D%7B5%7D)
Vol of a sphere = 4/3 x pi x r^3 = 24