Question

In an isolated population of 10,000 rabbits, 900 are homozygous for a recessive mutant Sp1 allele. Assuming the population is in Hardy-Weinberg equilibrium, what is the percentage of rabbits in the population that would be heterozygous for the mutant Sp1 allele

Answer 1

42% of rabbits in the population are heterozygous for the mutant Sp1 allele

Hardy-Weinberg equilibrium

• Assume that p is the frequency of the dominant allele
• p² is the frequency of the organisms with homozygous dominant genotype
• Assume that q is the frequency of the recessive allele
• q² is the frequency of the organisms with homozygous recessive genotype
• 2pq is the frequency of the organisms with heterozygous genotype
• p+q = 1

According to the question, 900 out of 10000 rabbits are homozygous recessive

• This implies that q² = 900/10000= 9/100= 0.09
• So, q = 0.3
• The frequency of the recessive allele is 0.3
• p = 1-q = 1-0.3= 0.7

For organisms with heterogenous genotype, their frequency is 2pq

2pq= 2 x 0.3 x 0.7 = 0.42

In terms of percentage, 0.42x 100% = 42%

Therefore, 42% of rabbits in the population are heterozygous for the mutant Sp1 allele.

Learn more about Hardy-Weinberg equilibrium here:

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