42% of rabbits in the population are heterozygous for the mutant Sp1 allele
Hardy-Weinberg equilibrium
- Assume that p is the frequency of the dominant allele
- p² is the frequency of the organisms with homozygous dominant genotype
- Assume that q is the frequency of the recessive allele
- q² is the frequency of the organisms with homozygous recessive genotype
- 2pq is the frequency of the organisms with heterozygous genotype
- p+q = 1
According to the question, 900 out of 10000 rabbits are homozygous recessive
- This implies that q² = 900/10000= 9/100= 0.09
- So, q = 0.3
- The frequency of the recessive allele is 0.3
- p = 1-q = 1-0.3= 0.7
For organisms with heterogenous genotype, their frequency is 2pq
2pq= 2 x 0.3 x 0.7 = 0.42
In terms of percentage, 0.42x 100% = 42%
Therefore, 42% of rabbits in the population are heterozygous for the mutant Sp1 allele.
Learn more about Hardy-Weinberg equilibrium here:
brainly.com/question/10482905
#SPJ10
