Answer:
48
Step-by-step explanation:
10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48,
Answer:
c
Step-by-step explanation:
dfnb fiqwebfibef
PQ is a radius. QS is tangent to the circle. In this scenario (a radius and a tangent passing through the same point of the radius) the two segments are always perpendicular.
This implies that PQS is a right triangle. We know that PQ = 10 because it's a radius.
Also, we have

because PR is a radius and RS is given.
So, we can derive QS using the pythagorean theorem:

I hope this helps you
x=89-61
x=28
Answer:

Step-by-step explanation:
In order to solve for this equation we have to note a couple of things.
There is a diagonal square inside a larger square. The space formed by the smaller square not being in the larger square is a right triangle.
The side length of the smaller square (4) is also the hypotenuse of this triangle.
Since we know that the other side length of the triangle is 3, we can use the Pythagorean Theorem to find the value of b.
The Pythagorean Theorem states that
, where a and b are the legs and c is the hypotenuse.
We can substitute 3 in as a and 4 in as c and find b.




So b is
units long.
Hope this helped!