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OleMash [197]
2 years ago
8

Doug split a pack of cards so that he and his friends each got 6 cards. If there were 24 cards in the pack, how many friends did

Doug share his cards with ?
Answer is not 4.
Mathematics
1 answer:
GuDViN [60]2 years ago
4 0

Answer:

3

Step-by-step explanation:

24 divided by 6 is 4, subtract Doug, there were 3 friends

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Amber had 6 cousins. Her friend Ashley has 2 fewer than 3 times as many cousins as Amber has. Which expression represents the nu
Olin [163]

Answer:

Cousins Amber has: 6

(Let no. of cousins Amber has be represented as x)

Cousins Ashley has: 3x - 2

(3 X 6)- 2

18-2

16

8 0
2 years ago
Find the equation of the line with slope = -7 and passing through (-7,51). write your equation in the form y=mx+b
muminat

Answer:

y = -7x + 2

Step-by-step explanation:

Since we do not have the y-intercept (or, when the x is 0) We will use the Slope Form Formula (y - y1 = m(x - x1)) to find the Slope Intercept Form Formula (y = mx + b)

Point: (-7,51)

Slope: -7

y - y1 = m(x - x1)

y - 51 = -7(x - (-7))

y - 51 = -7(x + 7)

y - 51 = -7x - 49

y = -7x - 49 + 51

y = -7x + 2

4 0
2 years ago
If x is a positive integer and y is a negative integer than x + y is a rational number.
romanna [79]

Answer:

Yes

Step-by-step explanation:

An integer is a whole number so if x is positive and y is negative then the equation would just be x plus negative y. But x+-y is an odd equation so the simplified version is x-y so it is a rational number, since a rational number is a number that can be rewritten as a simple fraction.

5 0
3 years ago
6<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%3F%7D%7B%3F%7D%20" id="TexFormula1" title=" \frac{?}{?} " alt=" \frac{?}{?}
alexdok [17]

Answer:

i don't get the question ...

Step-by-step explanation:

8 0
2 years ago
F(x)=2x^2 -5 , simplify f(x+h)/h , where h≠0
7nadin3 [17]

Answer:

\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}}

\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2-5}{h}+4x+2h}

Step-by-step explanation:

f(x)=2x^2-5\\\\\dfrac{f(x+h)}{h}=\dfrac{2(x+h)^2-5}{h}=\dfrac{2(x^2+2xh+h^2)-5}{h}\\\\\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}\\\\h\neq0

4 0
2 years ago
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