How to write a equation for the rRelationship Linear. Hour 2,3,4,5.quart 5,6.5,8,9.5 .how do you find equation for that

Mathematics

1 answer:

zalisa [80]3 years ago

8 0

I think you have to divide

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Given limit f(x) = 4 as x approaches 0. What is limit 1/4[f(x)]^4 as x approaches 0?

stepladder [879]

Answer:

$\displaystyle 64$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Rule [Variable Direct Substitution Exponential]: $\displaystyle \lim_{x \to c} x^n = c^n$

Limit Property [Multiplied Constant]: $\displaystyle \lim_{x \to c} bf(x) = b \lim_{x \to c} f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \lim_{x \to 0} f(x) = 4$

Step 2: Solve

Rewrite [Limit Property - Multiplied Constant]: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4} \lim_{x \to 0} [f(x)]^4$
Evaluate limit [Limit Rule - Variable Direct Substitution Exponential]: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4}(4^4)$
Simplify: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = 64$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

3 0

3 years ago

What is the difference in volume between a sphere with radius r and a sphere with radius 0.3r?

REY [17]

The volume of the sphere of radius r is:
V1 = (4/3) * (pi) * (r ^ 3)
Where,
r: sphere radius:
The volume of the sphere of radius 0.3r is:
V2 = (4/3) * (pi) * ((0.3r) ^ 3)
Rewriting:
V2 = (4/3) * (pi) * (0.027 (r) ^ 3)
V2 = 0.027 (4/3) * (pi) * (r ^ 3)
V2 = 0.027V1
The difference is:
V1-V2 = V1-0.027V1 = V1 (1-0.027)
V1-V2 = 0.973 * (4/3) * (pi) * (r ^ 3)
Answer:
the difference in volume between a sphere with radius and a sphere with radius 0.3r is:
V1-V2 = 0.973 * (4/3) * (pi) * (r ^ 3)

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3 years ago

Which image shows the correct position -2 1/2on the number line

Nat2105 [25]

Answer:

The first one

Step-by-step explanation:

8 0

3 years ago

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Is the square root of 400 rational or irrational

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