This is a Perimeter expression dissvolved from ones perspective in 2 SHAPES AND FORMS.
Hope this helps
Answer:
7
Step-by-step explanation:
All you have to do to solve this is subtract 18 from 25
Answer:
Find the area of a cardboard box with a length of 9 inches and a width of 4 inches.
Step-by-step explanation:
9 in × 4 in = 36 in²
The lowest number is - 3/2 or -1 1/2 as a mixed number (answer)
The we have greatest number which is 5/6 (answer) ( note there are 6 equal spaces between each integer value).
Difference between these numbers can be written as 5/6 - (-3/2)
= 5/6 - (-9/6) = 5/6 + 9/6
= 14/6
= 2 1/3 Answer
Also, difference = 5/6 - (-1 1/2)
= 5/6 + 1 + 1/2
= 5/6 + 6/6 + 3/6
= 14/6
= 2 1/3 (answer)
The volume is given by:
V = hx² = 500
We can then clear the height in terms of x:
h = 500 / x².
Area of the base: x²
Areal from the top: x²
Area of the vertical walls: 4xh = 4x (500 / x²) or 2000 / x
The formula sought will then be:
C = 0.15 (area of base) + 0.10 (area of top) + 0.025 (area of vertical walls)
C = 0.15x² + 0.10x² + 0.025 (2000 / x)
Rewriting:
C = .25x² + 50 / x
We derive and match zero to find the critical point:
0 = 0.5x - 50 / x ^ 2
Clearing x we have:
50 / x ^ 2 = 0.5x
x ^ 3 = 50 / 0.5
x ^ 3 = 100
x = 4.64
We derive again:
C '' (x) = 0.5 + 100 / x ^ 3
We evaluate x = 4.64:
C "(4.64) = 0.5 + 100 / (4.64) ^ 3
C '' (4.64)> 0 (x = 4.64 is a minimum)
Solving
h = 500 / x²
h = 500 / (4.64) ²
gives
h = 23.22.
Answer:
The dimensions of the box are 4.64 x 4.64 x 23.22.
The total cost would be $ 16.16.
