Answer:
- (x -3)(x+3)(2x +1)
- (x -1)(x +1)(x +3)
- (2x -1)(2x +1)(x -4)
Step-by-step explanation:
A) 2x³ +x² -18x -9 = x²(2x +1) -9(2x +1) = (x² -9)(2x +1) = (x -3)(x+3)(2x +1)
__
B) x³ +3x² -x -3 = x²(x +3) -1(x +3) = (x² -1)(x +3) = (x -1)(x +1)(x +3)
__
C) 4x³ -16x² -x +4 = 4x²(x -4) -1(x -4) = (4x² -1)(x -4) = (2x -1)(2x +1)(x -4)
_____
In each case, the third-level factoring mentioned in step 4 is the factoring of the difference of squares: a² -b² = (a -b)(a +b).
_____
The step-by-step is exactly what you need to do. It is simply a matter of following those instructions. You do have to be able to recognize the common factors of a pair of terms. That will be the GCF of the numbers and the least powers of the common variables.
Answer: A vertical stretch of 4 and a translation of -2 units in the x-direction.
Step-by-step explanation:
Changes of the parent function can be written, in this case as <em>a</em>f(x)(x - <em>k</em>) where <em>a</em> is the stretch factor and <em>k</em> is the movement left or right on the x-axis.
In this case, a = 4 and k = 2. Since the k is negative, the function will be moved -2 units on the x-axis.
<em>Learn more about </em><em>transformations of a parent function</em><em> here:</em>
<em>brainly.com/question/13822715</em>
Step-by-step explanation:
- Number of red = 2
- Number of blue = 5
- Number of green = 3
- total number of marbles = 10
<h3>
probability of not choosing a red marble = 1--choosing a red marble.</h3>
<u>Because</u><u> </u><u>probability</u><u> </u><u>is</u><u> </u><u>always</u><u> </u><u>one</u><u>(</u><u>1</u><u>)</u><u>.</u>
<em>Probability</em><em> </em><em>=</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>Is</em><em> </em><em>the</em><em> </em><em>probability</em><em> </em><em>of</em><em> </em><em>not</em><em> </em><em>choosing</em><em> </em><em>a</em><em> </em><em>red</em><em> </em><em>marble</em><em>.</em>
Answer:
If you want the improper fraction 43/8
If you want it in a decimal 5.375
Step-by-step explanation:
Answer: He got to be elected president of the Republic of Texas.
