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This is a common factor problem.
Pencils come in a pack of 12
Erasers come in a pack of 10
First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3
So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
We have (2*2*3) that comes from 12, and the only unique number that comes from the 10 is (5)
So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
60/12=5 packs of pencils
60/10= 6 packs of erasers
I hope this helps. Let me know if you have any questions!!
Equations are steeper when their slope's positive value is higher (ignore negatives when determining how steep a slope is). The slope is the value in front of x. If there isn't a value in front of x, then it is assumed to be 1.
Dan had 52
shown work: 29 x 2=58 58-6=52
Step-by-step explanation:
Line segment = EG
point on a line segment = F
EG = 100
EF = 4x - 20
FG = 2x + 30
a/q, EF + FG = EG
the equation is
4x - 20 + 2x + 30 = 100
now solution for x is
→ 4x - 20 + 2x + 30 = 100
→ 6x + 10 = 100
→ 6x = 100 - 10 = 90
→ x = 90/6 = 15
therefore, value of x is 15.
and according to given information
EF = 4x - 20 = 4(15) - 20 = 60 - 20 = 40
FG = 2x + 30 = 2(15) + 30 = 30 + 30 = 60
hope this answer helps you dear..take care and may u have a great day ahead!
