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ValentinkaMS [17]
2 years ago
7

Use the coordinates of the labeled point to find the point-slope equation of the line

Mathematics
2 answers:
emmasim [6.3K]2 years ago
5 0

Answer:

C

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (2, - 1) ← 2 points on the line

m = \frac{-1-3}{2-0} = \frac{-4}{2} = - 2

using (a, b ) = (2, - 1 ) , then

y - (- 1) = - 2(x - 2) , that is

y + 1 = - 2(x - 2)

just olya [345]2 years ago
5 0

Answer: A

Step-by-step explanation:

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valentina_108 [34]

Step-by-step explanation:

\frac{5}{2}  =  \frac{x - 4}{3}

3 \times \frac{5}{2}  =  \frac{x - 4}{3}

\frac{3}{1}  \times  \frac{5}{2}  =  \frac{x - 4}{3}

cross multiplication

\frac{6 \times 5}{2}  =  \frac{x - 4}{3}

15 =  \frac{x - 4}{3}

15 \times 3 = x - 4

45 + 4 = x

49 = x

4 0
3 years ago
Read 2 more answers
Solve the equation
inysia [295]

Answer:

x ≈ 1.32, x ≈ - 5.32

Step-by-step explanation:

Given

x² + 4x - 7 = 0 ( add 7 to both sides )

x² + 4x = 7

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(2)x + 4 = 7 + 4

(x + 2)² = 11 ( take the square root of both sides )

x + 2 = ± \sqrt11} ( subtract 2 from both sides )

x = - 2 ± \sqrt{11}

Thus

x = - 2 - \sqrt{11} ≈ - 5.32 ( to 2 dec. places )

x = - 2 + \sqrt{11} ≈ 1.32 ( to 2 dec. places )

8 0
3 years ago
Read 2 more answers
What are the partial products for 43 x 17
Lelechka [254]
The partial products would be 10 multiply 40, 10 multiply 3, 7 multiply 40, and 7 multiply 3.
4 0
3 years ago
Lance baked a pie Justin ate 2/3 of the pie and Joey ate 1/4 of the pie how much of the pie is left
zepelin [54]
1 - 2/3 - 1/4
= 1 - 8/12 - 3/12
= 1/12
8 0
3 years ago
does somebody knows how to do this one?
vlada-n [284]

Answer:

Step-by-step explanation:

To find the area subtract the area of the semicircle from the area of the rectangle.

Although the line isn’t there, if you imagine there is one, then you will see that you form a rectangle which is the same line as the semicircle’s diameter.

The area of rectangle is:

⇒ A = lw

⇒ A = (14)(8)

⇒ A = 112cm^{2}

The area of the semicircle;

⇒ A = \frac{1}{2}\pi r^{2}

⇒ A = \frac{1}{2}\pi (7)^{2}

*Note here that the radius is half the diameter, so it is 7cm, not 14cm

⇒ A = 76.97cm^{2}

Finally subtract the two areas;

⇒ A = 112 - 76.97

⇒ A = 35.03cm^{2}

6 0
2 years ago
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