What is the graphing points of y=3x-8

Just ignore number 7 it’s 8 I need help on, it tried to attempt it myself but it wasn’t working for me

ArbitrLikvidat [17]

1 hm=100m

1.5hm=150 meters each tower is from each other.

500km(1000m/1km)=500,000 meters the wire covers.

500,000/150 = 3333.33 towers. Just because we want to be safe and have enough towers we can say we have 3334 towers in the span of 500,000 meters.

B)

1kV=1000V

500kV(1000V/1kV)= 500,000 V

There are 1.2 volts in a AA battery so we divide 500,000/1.2 = 416666.67 times larger

3 0

3 years ago

How can you tell that the data in the table is function or not?

stealth61 [152]

that is not a function, because there are two outputs for three. two inputs can have one output, but one input cant have two outputs.

6 0

2 years ago

Use undetermined coefficient to determine the solution of:y"-3y'+2y=2x+ex+2xex+4e3x

Kitty [74]

First check the characteristic solution: the characteristic equation for this DE is

r ² - 3r + 2 = (r - 2) (r - 1) = 0

with roots r = 2 and r = 1, so the characteristic solution is

y (char.) = C₁ exp(2x) + C₂ exp(x)

For the ansatz particular solution, we might first try

y (part.) = (ax + b) + (cx + d) exp(x) + e exp(3x)

where ax + b corresponds to the 2x term on the right side, (cx + d) exp(x) corresponds to (1 + 2x) exp(x), and e exp(3x) corresponds to 4 exp(3x).

However, exp(x) is already accounted for in the characteristic solution, we multiply the second group by x :

y (part.) = (ax + b) + (cx ² + dx) exp(x) + e exp(3x)

Now take the derivatives of y (part.), substitute them into the DE, and solve for the coefficients.

y' (part.) = a + (2cx + d) exp(x) + (cx ² + dx) exp(x) + 3e exp(3x)

… = a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)

y'' (part.) = (2cx + 2c + d) exp(x) + (cx ² + (2c + d)x + d) exp(x) + 9e exp(3x)

… = (cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

Substituting every relevant expression and simplifying reduces the equation to

(cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

… - 3 [a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)]

… +2 [(ax + b) + (cx ² + dx) exp(x) + e exp(3x)]

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

… … …

2ax - 3a + 2b + (-2cx + 2c - d) exp(x) + 2e exp(3x)

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

Then, equating coefficients of corresponding terms on both sides, we have the system of equations,

x : 2a = 2

1 : -3a + 2b = 0

exp(x) : 2c - d = 1

x exp(x) : -2c = 2

exp(3x) : 2e = 4

Solving the system gives

a = 1, b = 3/2, c = -1, d = -3, e = 2

Then the general solution to the DE is

y(x) = C₁ exp(2x) + C₂ exp(x) + x + 3/2 - (x ² + 3x) exp(x) + 2 exp(3x)

4 0

2 years ago

HELPP!!!! 100 points. Which expression is equivalent

devlian [24]

Answer:

$\Large \boxed{\sf A}$

Step-by-step explanation:

$\displaystyle 2x\sqrt{44x}-2\sqrt{11x^3}$

Let x = 2 because x > 0

$\displaystyle 2(2)\sqrt{44(2)}-2\sqrt{11(2)^3}=4\sqrt{22}$

See which expression is equal to 4√22 when x = 2

$2(2)\sqrt{11(2)}=4\sqrt{22}$

The expression is option A

8 0

2 years ago

Read 2 more answers

I neeeeeed help please!!!!!!!!!!!

Helga [31]

Answer:

2

Step-by-step explanation:

Its pretty easy math

6 0

3 years ago