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Dmitrij [34]
2 years ago
10

What is the equation for a circle with a radius of 7 and center at ( - 6,2)?

Mathematics
2 answers:
Sunny_sXe [5.5K]2 years ago
8 0

Answer:

(x+6) squared + (y-2) squared = 49

Step-by-step explanation:

olganol [36]2 years ago
7 0

Answer:

(x + 6)² + (y - 2)² = 49

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

here (h, k ) = (- 6, 2 ) and r = 7 , then

(x - (- 6) )² + (y - 2)² = 7² , that is

(x + 6)² + (y - 2)² = 49

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At what point on the graph of y=1/4x^4 is the tangent line parallel to the line 24x -3y=8
Rama09 [41]

Answer:

a) dy/dx = 4/(2y+1)^2.

(b) y = 4/9 x - 14/9

(c) d2y/dx2 = -64/243

Step-by-step explanation:

You have the following equation

  (1)

(a) You first derivative implicitly the equation (1) respect to x:

next, you solve the last result for dy/dx:

(2)

(b) The equation for the tangent line is given by:

   (3)

with yo = -2 and xo = -1

To find the slope m you use the result of the equation (2), because dy/dx evaluated in (-1,-2) is the slope at such point:

m =

Hence, by replacing in the equation (3) you obtain:

hence, the equation for the tangent line is y = 4/9 x - 14/9

(c) To find d2y/dx2 you derivative the result obtain in the equation (2):

    (4)

the second derivative for the point (-1,-2) is obtained by replacing y=-2 and dy/dx=m=4/9 in the equation (4):

hence, d2y/dx2 evaluated in (-1,-2) is -64/243

Step-by-step explanation:

3 0
3 years ago
B) A shopkeeper sold her goods for Rs 16,950 allowing 25 % discount and then levied on
Damm [24]

Answer:

Please mark it as the brainliest...

7 0
3 years ago
19. Calculate the size of the angle marked x in the diagram.
algol [13]

Answer:

151°

Step-by-step explanation:

126°+221°+95°+57°+70+x=720° ( sum of interior angles of hexagon)

x + 569° =720°

x = 720°- 569°

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7 0
3 years ago
Read 2 more answers
Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute
valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

       = 3 - 1 = 2

d.f.D = N - k

        = 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust                      Jet red                 Cloudtran

$\overline X_1 =50.5$           $\overline X_2 =50.07143$        $\overline X_3 =55.71429$

$s_1^2=19.96154$      $s_2^2=14.68681$         $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

         $=\frac{51+51+...+49+49}{35}$

        = 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

     $=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

   $=\frac{127.1143}{2}$

   = 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

    $=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

   $=\frac{669.8571}{32}$

  = 20.93304

The F-test  statistics value is :

$F=\frac{s_B^2}{s_W^2}$

  $=\frac{63.55714}{20.93304}$

  = 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source       Sum of squares    d.f    Mean square    F

Between    127.1143                 2      63.55714          3.036212

Within        669.8571             32      20.93304

Total           796.9714            34

3 0
3 years ago
Find the circumference.<br> Use 3.14 for n.<br> r = 6 ft<br> C = [?] ft<br> C=Td
Y_Kistochka [10]

In the circumference formula given d is the diameter which is 2 times r ( r is the radius)

R is given as 6 feet, diameter = 2 x 6 = 12 feet.

Circumference = 12 feet x 3.14 = 37.68 feet

5 0
3 years ago
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