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masya89 [10]
2 years ago
5

1. Create an ungrouped frequency distribution table with the data from the survey concerning the age of the people, which attend

the gym. The results of a survey are presented below.

Mathematics
1 answer:
lukranit [14]2 years ago
4 0

Answer:

firstly ,we need to put the set of  ages into categories

Example: (Category1 = age 19  ; category2 = age 20  ; ........ )

→ The frequency of a certain value (age) is equal to the number of times that specific age appears in the data set.

Step-by-step explanation:

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Suppose the heights of a population of people are normally distributed with a mean of 65.5 inches and a standard deviation of 2.
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Answer:

a) P(64.2

b) 69.764

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(65.5,2.6)

Where \mu=65.5 and \sigma=2.6

We are interested on this probability

P(64.2

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(64.2

And we can find this probability on this way:

P(-0.50

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

P(-0.50

3) Part b

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.05   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64. On this case P(Z<1.64)=0.95 and P(z>1.64)=0.05

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.64

And if we solve for a we got

a=65.5 +1.64*2.6=69.764

So the value of height that separates the bottom 95% of data from the top 5% is 69.764.

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Answer:

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