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3 years ago

The polar form of (-1,√3) is(_,_)

Mathematics

1 answer:

Klio2033 [76]3 years ago

4 0

Answer:

(2, 2/3 * pi)

Step-by-step explanation:

( -1, sqrt(3))

to find the radius

sqrt(x^2 + y^2) = r

sqrt( (-1)^2 + (sqrt3)^2) = r

sqrt(1+3) =r

sqrt(4) =r

2=r

to find theta

theta = arctan (sqrt(3)/-1)

theta = -60 degrees

you need theta between 90 and 180

add 180 to theta

theta = 120

you need theta in radians

120 * pi/180 = 2/3 * pi

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Find the projection of the vector A = î - 2ġ + k on the vector B = 4 i - 4ſ + 7k. 15. Given the vectors A = 2 i +3 ſ +6k and B =

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Part 1)

Projection of vector A on vector B equals 19 units

Part 2)

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Step-by-step explanation:

For 2 vectors A and B the projection of A on B is given by the vector dot product of vector A and B

Given

$\overrightarrow{v_{a}}=\widehat{i}-2\widehat{j}+\widehat{k}$

Similarly vector B is written as

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$\overrightarrow{v_{a}}\cdot \overrightarrow{v_{b}}=(\widehat{i}-2\widehat{j}+\widehat{k})\cdot (4\widehat{i}-4\widehat{j}+7\widehat{k})\\\\\overrightarrow{v_{a}}\cdot \overrightarrow{v_{b}}=1\cdot 4+2\cdot 4+1\cdot 7=19$

Part 2)

Given vector A' as

$\overrightarrow{v_{a'}}=2\widehat{i}+3\widehat{j}+6\widehat{k}$

Similarly vector B' is written as

$\overrightarrow{v_{b'}}=\widehat{i}+5\widehat{j}+3\widehat{k}$

Thus the vector dot product of the 2 vectors is obtained as

$\overrightarrow{v_{b'}}\cdot \overrightarrow{v_{a'}}=(\widehat{i}+5\widehat{j}+3\widehat{k})\cdot (2\widehat{i}+3\widehat{j}+6\widehat{k})\\\\\overrightarrow{v_{a'}}\cdot \overrightarrow{v_{b'}}=1\cdot 2+5\cdot 3+3\cdot 6=35$

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4 years ago

HELP ME ASAP!!!!!!!!

Natali5045456 [20]

#9
99 cent for 100 paper
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multiply 100 and 5=500
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the better deal would be $4.29 for 500 paper

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3 years ago

Write a different expression equivalent to 4.5(x+3)

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Hey there!

4.5(x + 3)

= 4.5(x) + 4.5(3)

= 4.5x + 13.5

Therefore, your answer is: 4.5x + 13.5

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

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Read 2 more answers

The polar form of (-1,√3) is(___,___)

The polar form of (-1,√3) is(_,_)