Answer: Q=1.79
Step-by-step explanation: Move 0.63 to the right and add both numbers then calculate it. So Q=1.79
<u>Given</u>:
Given that O is the center of the circle.
The radius of the circle is 3 m.
The measure of ∠AOB is 30°
We need to determine the length of the major arc ACB
<u>Measure of major ∠AOB:</u>
The measure of major angle AOB can be determined by subtracting 360° and 30°
Thus, we have;


Thus, the measure of major angle is 330°
<u>Length of the major arc ACB:</u>
The length of the major arc ACB can be determined using the formula,
<u></u>
<u></u>
Substituting r = 3 and
, we get;



Thus, the length of the major arc ACB is 5.5π m
Answer:
length PQ = 8.9 m
Step-by-step explanation:
The picture below completes the question you asked. From the picture above RSTU is a rectangle . The two shaded square has a length of sides 8 m and 4 m respectively. The legs of the triangle is the sides of the 2 squares. Therefore, the triangle is a right angle triangle. The adjacent side is 4 m while the opposite side is 8 m.
Using Pythagoras theorem the hypotenuse of the triangle can be calculated below.
Pythagoras theorem
c² = a² + b² Therefore,
c² = 4² + 8²
c² = 16 + 64
c² = 80
square root both sides
c = √80
c = 8.94427191
c ≈ 8.9 m
length PQ = 8.9 m
Can of baked beans = x
packet of brown sugar = y
packet of biscuit = z
5x + 4y + 2z = 150 - 26 ⇒ 5x + 4y + 2z = 124 is the total cost of all items.
can of baked beans = x = 1/2 of z
packet of sugar = y = z - 3
5(z/2) + 4(z-3) + 2z = 124
5z/2 + 4z - 12 + 2z = 124
5z/2 + 6z = 124 + 12
2(5z/2 + 6z) = 2(136)
5z + 12z = 272
17z = 272
z = 16 cost of a packet of biscuit.
x = 1/2 of z = 16/2 = 8 cost of a can of baked beans
y = z - 3 = 16 - 3 = 13 cost of a packet of sugar
5x + 4y + 2z = 124
5(8) + 4(13) + 2(16) = 124
40 + 52 + 32 = 124
124 = 124
8(8) + 1(13) + 6(16) = 64 + 13 + 96 = 173 total cost on question 3.