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2 years ago

HELP ME PLEASE!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Pepsi [2]2 years ago

6 0

The ordered pairs of the solution to the system of equation are [(3, 6), (-3, 18)]

<h3>System of equations</h3>

Given the following system of equations expressed as:

f(x) = x² - 2x + 3 and f(x) = -2x + 12

Since they are both function of x, hence;

x² - 2x + 3 = -2x + 12

x² - 2x + 3 + 2x - 12 = 0

x² - 9 = 0

x² = 9

x = ±√9

x = ±3

If x = 3

f(x) = -2(3) + 12

f(x) = 6

If x = -3

f(x) = -2(-3) + 12

f(x) =18

Hence the ordered pairs of the solution to the system of equation are [(3, 6), (-3, 18)]

Learn more on system of equation here: brainly.com/question/14323743

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3 years ago

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Answer:

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We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

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$15x((x^2-3x)+(2x-6))=0$

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$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

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3 years ago

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Step-by-step explanation:

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