Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
Your answer would be, Yes! It is an Isosceles Trapezoid, Because, Isosceles trapezoids have at least one set of opposite sides, that are parallel, mainly the base, and it's opposite. The non-base sides are equal in length to each other, and the base angles are equal to each other.
Hope that helps!!!!!!
Answer:
Okay so number 3 is either undefined or Zero. I always forget which is which.
Step-by-step explanation:
But for 1 and 2 use your solution m=rise/run. Or you could count the ways down, like say, for number 1 it runs over 3 from a point and goes up till the next point. I hope this helps.
Answer:
x > -4
Step-by-step explanation:
Inequalities like these are solved the same way equations are solved, except when multiplying both sides you flip the less than/greater than sign:
3x + 7 > -x -9
3x + 7 - 7 > -x -9 -7 Subtract 7 from both sides
3x > -x -16
3x + x > -x -16 + x add x to both sides
4x > -16
> 
divide both sides by 4
x > -4
In this case the inequality sign did not have to be flipped since we never multiply both sides by a negative number.
Answer:
Your right
Step-by-step explanation:
