Answer:
the two positive consecutive integers are 4 and 6.
Step-by-step explanation:
Let the smaller integer be s; then s^2 = (s + 2) + 10.
Simplifying, s^2 - s - 2 - 10 = 0, or
s^2 - s - 12 = 0.
Solve this by factoring: (s - 4)(s + 3) = 0.
Then s = 4 and s = -3.
If the first even integer is 4, the next is 6. We omit s = -3 because it's not even.
The smaller integer is 4. Does this satisfy the equation s^2 = (s + 2) + 10?
4^2 = (4 + 2) + 10 True or False?
16 = 6 + 10 = 16.
True.
So the two positive consecutive integers are 4 and 6.
Answer:
Step-by-step explanation:
y+1 =(3/4)x+9/4
y=(3/4)x+1/4
Answer: 272.85
(It’s 21.4 times 12.75)
X=
Or it would be approximately: x≈ 0.37228132, -5.37228132
Hope this helped! ;P
Answer:
6, -4
Step-by-step explanation:
abs(-1+x)=5
-1+x=5 and -1+x=-5
-------------------------
-1+x=5
x=5-(-1)=5+1=6
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-1+x=-5
x=-5-(-1)=-5+1=-4
