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anzhelika [568]
3 years ago
15

I need help pleasee..

Mathematics
1 answer:
siniylev [52]3 years ago
7 0

Answer:

c, i and 3

Step-by-step explanation:

if you look at the congruence signs, then you will see that the 70 degree angle is in the same place.

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MATH <br> can somebody help me with these questions?
Dmitriy789 [7]
I’m learning this in class as well
Ok so basically you just need to find 2 random points so like (30,100) and (20,30)
And my question for you is do you know the equation format?

6 0
2 years ago
In circle M, segment AB is tangent to the circle at point C. AB has endpoints such that AM BM  ,
iren2701 [21]

Answer:

6

Step-by-step explanation:

We can use the geometric mean theorem:

The altitude on the hypotenuse is the geometric mean of the two segments it creates.

In your triangle, the altitude is the radius CM and the segments are AC and BC.

CM = \sqrt{AC \times BC} = \sqrt{ 9 \times 4} = \sqrt{36} = \mathbf{6}\\\text{The radius of the circle M is $\large \boxed{\mathbf{6}}$}

5 0
3 years ago
V = e^3 when e = 7 please help me​
Nuetrik [128]

Answer:

343

Step-by-step explanation:

7^3=7×7×7=343

If e is equal to 7 just multiply 7 by 7 and then multiply that answer by 7 to find 7 to the power of 3.

7 0
3 years ago
Slope i cant seem to figure out run/rise can anyone also help me with that too thank you
Savatey [412]
The slope of the line is -3/4
7 0
3 years ago
Find the minimum and maximum possible areas of a rectangle measuring 6 km by 11 km.
ExtremeBDS [4]
Assuming your numbers are rounded to the nearest km, the minimum area will be ...
  (5.5 km)·(10.5 km) = 57.75 km² . . . minimum

And the maximum area will be ...
  (6.5 km)·(11.5 km) = 74.75 km² . . . maximum

_____
When a number is rounded to 6 km as the nearest km, its value may actually be anywhere in the range 6 km ± 0.5 km. If you really want to get technical about it, the ranges of possible dimensions are [5.5, 6.5) km and [10.5, 11.5) km, and the range of possible areas is [57.75, 74.75) km².
3 0
3 years ago
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