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2 years ago

15

The graph of a sinusoidal function has a minimum point at (0,3)(0,3)left parenthesis, 0, comma, 3, right parenthesis and then in

tersects its midline at (5\pi,5)(5π,5)left parenthesis, 5, pi, comma, 5, right parenthesis.

1 answer:

laiz [17]2 years ago

5 0

Answer:

the answer is left,5 right 6 and left 7

Step-by-step explanation:

hope it helps

You might be interested in

Pls help with both 19 and 20 I’ll mark brainliest, show how you set up the problems

belka [17]

<h2>Answer:</h2>

<u>Question 19:</u>

Option A:

40 x 19 = 760

Option B:

A: 9,500 x 8 = 76,000

76,000 ÷ 100 = 760

B: 4,750 x 8 = 38,000

38,000 ÷ 100 = 380

C: 760 x 8 = 6,080

6,080 ÷ 100 = 60.8

D: 320 x 8 = 2,560

2,560 ÷ 100 = 25.6

<em>Answer:</em> $9,500

<u>Question 20:</u>

5.5 x 30 = 165

165 ÷ 100 = 1.65

1.65 + 5.5 = 7.15

Commission: 7.15%

382,000 x 7.15 = 2,731,300

2,731,300 ÷ 100 = 27,313

<em>Answer:</em> The agent earns $27,313 in commissions.

4 0

3 years ago

Line C and D are perpendicular. If the slope of a line c is -4, what is the slope of line D?

andrew11 [14]

Answer:

1/4

Step-by-step explanation:

The slope of a line is the steepness of a line.

The slope of a perpendicular line is always the negative reciprocal of the slope of the line it is perpendicular with.

Since line C has a slope of -4, the negative reciprocal of that is 1/4.

Reciprocals are two numbers that multiply together to get 1.

For example, -1/4*-4/1=1

Therefore the negative recipricol is 1/4

4 0

4 years ago

Read 2 more answers

Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a

kipiarov [429]

Answer:

a) P(k≤11) = 0.021

b) P(k>23) = 0.213

c) P(11≤k≤23) = 0.777

P(11<k<23) = 0.699

d) P(15<k<25)=0.687

Step-by-step explanation:

a) What is the probability that the number of drivers will be at most 11?

We have to calculate P(k≤11)

$P(k\leq11)=\sum_0^{11} P(k$

$P(k=0) = 20^0e^{-20}/0!=1 \cdot 0.00000000206/1=0\\\\P(k=1) = 20^1e^{-20}/1!=20 \cdot 0.00000000206/1=0\\\\P(k=2) = 20^2e^{-20}/2!=400 \cdot 0.00000000206/2=0\\\\P(k=3) = 20^3e^{-20}/3!=8000 \cdot 0.00000000206/6=0\\\\P(k=4) = 20^4e^{-20}/4!=160000 \cdot 0.00000000206/24=0\\\\P(k=5) = 20^5e^{-20}/5!=3200000 \cdot 0.00000000206/120=0\\\\P(k=6) = 20^6e^{-20}/6!=64000000 \cdot 0.00000000206/720=0\\\\P(k=7) = 20^7e^{-20}/7!=1280000000 \cdot 0.00000000206/5040=0.001\\\\$

$P(k=8) = 20^8e^{-20}/8!=25600000000 \cdot 0.00000000206/40320=0.001\\\\P(k=9) = 20^9e^{-20}/9!=512000000000 \cdot 0.00000000206/362880=0.003\\\\P(k=10) = 20^{10}e^{-20}/10!=10240000000000 \cdot 0.00000000206/3628800=0.006\\\\P(k=11) = 20^{11}e^{-20}/11!=204800000000000 \cdot 0.00000000206/39916800=0.011\\\\$

$P(k\leq11)=\sum_0^{11} P(k$

b) What is the probability that the number of drivers will exceed 23?

We can write this as:

$P(k>23)=1-\sum_0^{23} P(k=x_i)=1-(P(k\leq11)+\sum_{12}^{23} P(k=x_i))$

$P(k=12) = 20^{12}e^{-20}/12!=8442485.238/479001600=0.018\\\\P(k=13) = 20^{13}e^{-20}/13!=168849704.75/6227020800=0.027\\\\P(k=14) = 20^{14}e^{-20}/14!=3376994095.003/87178291200=0.039\\\\P(k=15) = 20^{15}e^{-20}/15!=67539881900.067/1307674368000=0.052\\\\P(k=16) = 20^{16}e^{-20}/16!=1350797638001.33/20922789888000=0.065\\\\P(k=17) = 20^{17}e^{-20}/17!=27015952760026.7/355687428096000=0.076\\\\P(k=18) = 20^{18}e^{-20}/18!=540319055200533/6402373705728000=0.084\\\\$

$P(k=19) = 20^{19}e^{-20}/19!=10806381104010700/121645100408832000=0.089\\\\P(k=20) = 20^{20}e^{-20}/20!=216127622080213000/2432902008176640000=0.089\\\\P(k=21) = 20^{21}e^{-20}/21!=4322552441604270000/51090942171709400000=0.085\\\\P(k=22) = 20^{22}e^{-20}/22!=86451048832085300000/1.12400072777761E+21=0.077\\\\P(k=23) = 20^{23}e^{-20}/23!=1.72902097664171E+21/2.5852016738885E+22=0.067\\\\$

$P(k>23)=1-\sum_0^{23} P(k=x_i)=1-(P(k\leq11)+\sum_{12}^{23} P(k=x_i))\\\\P(k>23)=1-(0.021+0.766)=1-0.787=0.213$

c) What is the probability that the number of drivers will be between 11 and 23, inclusive? What is the probability that the number of drivers will be strictly between 11 and 23?

Between 11 and 23 inclusive:

$P(11\leq k\leq23)=P(x\leq23)-P(k\leq11)+P(k=11)\\\\P(11\leq k\leq23)=0.787-0.021+ 0.011=0.777$

Between 11 and 23 exclusive:

$P(11< k$

d) What is the probability that the number of drivers will be within 2 standard deviations of the mean value?

The standard deviation is

$\mu=\lambda =20\\\\\sigma=\sqrt{\lambda}=\sqrt{20}= 4.47$

Then, we have to calculate the probability of between 15 and 25 drivers approximately.

$P(15$

$P(k=16) = 20^{16}e^{-20}/16!=0.065\\\\P(k=17) = 20^{17}e^{-20}/17!=0.076\\\\P(k=18) = 20^{18}e^{-20}/18!=0.084\\\\P(k=19) = 20^{19}e^{-20}/19!=0.089\\\\P(k=20) = 20^{20}e^{-20}/20!=0.089\\\\P(k=21) = 20^{21}e^{-20}/21!=0.085\\\\P(k=22) = 20^{22}e^{-20}/22!=0.077\\\\P(k=23) = 20^{23}e^{-20}/23!=0.067\\\\P(k=24) = 20^{24}e^{-20}/24!=0.056\\\\$

3 0

3 years ago

A rectangle has sides of length 6.1cm and 8.1cm correct to one decimal place.

tamaranim1 [39]

The area is 49.41

6.1x8.1

8 0

3 years ago

Read 2 more answers

Allen is showing us work in simplifying – 8.3+9.2-4.4+3.7 point identify and explain any errors in his work in or in his reasoni

vladimir1956 [14]

Answer: -8.3 + 9.2 - 4.4 + 3.7

= -8.3 + 9.2 + (-4.4) + 3.7 {Additive inverse}

= -8.3 + (-4.4) + 9.2 + 3.7 {Commutative Property}

= [ -8.3 + (-4.4] + [ 9.2 + 3.7] {Associative property}

= - 12.7 + 12.9

= 0.2

Step-by-step explanation: I copied it from someone hope it helps though! :D

5 0

3 years ago