Answer:
First Option: cos(x)
Step-by-step explanation:
What is given is csc(x) = 14/10
The graph lies in the first quadrant since 0 < x < pi/2
Create a triangle:
The length across is 14
The adjacent is 10
The length of the shorter side is root 96
Use the pythagorean theorem
BC^2 = 14^2 - 10^2
BC^2 = 196 - 100, 96
BC^2 = root 96/14
Recall SOH-CAH-TOA
Adjacent over Hypotenuse is cos
That is how the answer is cos(x)
With the mean and range, we can estimate the weights of the smallest and largest animals in each group.
For cats the interval is [ 3.75kg, 4.25kg] and for dogs is [9.5kg, 54.5kg]
<h3>
Which conclusions can be made with the given information?</h3>
We know that the mean weight for cats is 4kg, and the range (difference between the largest value and smallest value) is 0.5kg.
- From that, we can conclude with some confidence (but not exactly), that the largest cat weights 4kg + 0.5kg/2 = 4.25kg
- And the smallest cat weights 4kg - 0.5kg/2 = 3.75kg
(Assuming a normal distribution).
Similar for the dogs, the mean weight is 32kg and the range is 45kg, then:
- The largest dog weights 32kg + 45kg/2 = 54.5kg
- The smallest dog weights 32kg - 45kg/2 = 9.5kg
(again, assuming a normal distribution).
If you want to learn more about means and ranges:
brainly.com/question/14532771
#SPJ1
Since it is 4 times as many quarters and dimes, you can use a chart for guess and check. I started with 8 dimes and 32 quarters.
If you keep going, you end up with the fact that there are 36 quarters and 9 dimes.
Answers:
a) 1/6
b) 0
Step-by-step explanation:
a) this is the way i remember
on a 6 sided dice there are <em>6</em> outcomes. 5 is 1 of those outcomes. so its 1/<em>6</em>
b) there no 7 on a six sided dice so its impossible. impossible outcomes are represented as 0
Answer:
450L
Step-by-step explanation:
This is a ratio and proportion problem. First you need to determine the known ratio and the unknown ratio. In this case we have the known ratio:
The unknown ratio in this case is:
So to do this, we just set up the proportion and solve for it:
