Answer:
It's number three, I'm sure.

Step-by-step explanation:
Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is
is correct answer
Therefore
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
( using the property
)
( using the property 
( combining the like powers )
( using the property
)

( using the property
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is
is correct answer
Answer:
1080"
Step-by-step explanation:
12*10= 120
120*9= 1080
Answer:
5/9
Step-by-step explanation:
What we have in this question are four white balls and 5 red balls.
This is the sample space
[(4w,0R) (4w,1R)(4w,2R)(4w,3R)(4w,4R)(0w,5R)(1w,5R)(2w,5R)
So we have 9 possible sets of events
The event number with the last ball being white = 5
Probability of the last ball drawn being white = 5/9
= 0.56