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3 years ago

Find the mean of the integers: 7,-9,9,-7,0

Mathematics

1 answer:

Aleks04 [339]3 years ago

7 0

Step-by-step explanation:

Add all of the numbers together

7 + 9 + 0 + (-9) + (-7)

simplify it down to:

(7+9+0)= 16

-9 + (-7)= - 16

So, -16 + 16 = 0

then divide 0 by 5 to get the answer of 0

To find the mean you have to add all of the numbers together and then divide by the amount of numbers that you have.

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The sum of two numbers is 99 and the difference is 13. Use a system of two equations and two variables to solve and find the two

andriy [413]

Answer:

56 and 43

Step-by-step explanation:

(x+13)+x = 99

2x+13 = 99

2x = 99-13

2x = 86

x = 86/2

x = 43

Smaller number = 43

Larger number is 56

Check

56-43 = 13

56+43 = 99

7 0

3 years ago

Read 2 more answers

The cost to produce a product is modeled by the function f(x) = 5x^2 − 70x + 258, where x is the number of products produced. Co

Advocard [28]

The minimum of a quadratic function, with a positive coefficient a, is its vertex.

Let's find the x₀ coordinate.

$f(x) = 5x^2 -70x + 258\\\\x_0=\dfrac{-b}{2a}=\frac{-(-70)}{2*5} =\frac{70}{10} =7$

Now we need to find y₀ coordinate. That will be the minimum of function.

$y_0=5\times7^2-70\times7+258=13$

So, the minimum cost to produce the product is $13

Decompose 5x^2 − 70x + 258 into multipliers

$5x^2 - 70x + 258=(5x^2-70x+245)+13=5(x^2-14+49)+13=\\=5(x-7)^2+13$

Answer: 5(x − 7)^2 + 13; The minimum cost to produce the product is $13.

4 0

3 years ago

Complete parts (a) through (c) below. (a) Determine the critical value(s) for a right-tailed test of a population mean at t

olga_2 [115]

Answer:

a) The critical value on this case would be $t_{crit}=1.325$

b) The critical value on this case would be $t_{crit}=-1.345$

c) The critical values on this case would be $t_{crit}=\pm 2.201$

Step-by-step explanation:

Part a

The system of hypothesis on this case would be:

Null hypothesis: $\mu \leq \mu_0$

Alternative hypothesis: $\mu > \mu_0$

Where $\mu_0$ is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, on this case that is given df=20. Since its an upper tailed test we need to find a value a such that:

$P(t_{20}>a) = 0.1$

And we can use excel in order to find this value with this function: "=T.INV(0.9,20)". The 0.9 is because we have 0.9 of the area on the left tail and 0.1 on the right.

The critical value on this case would be $t_{crit}=1.325$

Part b

The system of hypothesis on this case would be:

Null hypothesis: $\mu \geq \mu_0$

Alternative hypothesis: $\mu < \mu_0$

Where $\mu_0$ is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, given by:

$df=n-1=15-1=14$

Since its an lower tailed test we need to find b value a such that:

$P(t_{14}$

And we can use excel in order to find this value with this function: "=T.INV(0.1,14)". The 0.1 is because we have 0.1 of the area accumulated on the left of the distribution.

The critical value on this case would be $t_{crit}=-1.345$

Part c

The system of hypothesis on this case would be:

Null hypothesis: $\mu = \mu_0$