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2 years ago

-6b(8b-2)-3b(4+4b) simplify equation

Mathematics

1 answer:

dybincka [34]2 years ago

7 0

-6b(8b - 2) - 3b(4 + 4b) ...distribute thru the parenthesis
-48b^2 + 12b - 12b - 12b^2 =
-48b^2 - 12b^2 =
-60b^2 <==

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16.BONUS:

Viktor [21]

Answer: 11.38

Step-by-step explanation:

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2 years ago

How much is 3/4 cup & 3/4 cup =

Anarel [89]

3/4 of a cup plus 3/4 of a cup equals one and a half cups 3/4 cup plus 1/4 equals one cup and that leaves 1.3 cup so answer is one and a half cups

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2 years ago

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What is true about the angles in the diagram show below? Please Help!

dsp73

Answer:

1) 30

2) 60

Step-by-step explanation:

1. 90 + 2x + x = 180

solve for x

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plug in 30 for x

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1 year ago

Data from the U.S. Department of Education indicates that 59% of business graduate students from private universities had studen

san4es73 [151]

Answer: The mean of this distribution = 61.95

The standard deviation of this sampling distribution (i.e., the standard error= 0.048

Step-by-step explanation:

Given : Data from the U.S. Department of Education indicates that 59% of business graduate students from private universities had student loans.

i.e. proportion of business graduate students from private universities had student loans : p=0.59

sample size : n=105

Then , the mean of the distribution is given by :-

$\mu= np = (105)(0.59)=61.95$

∴The mean of this distribution = 61.95

Then standard deviation of this sampling distribution is given by :-

$\sqrt{\dfrac{p(1-p)}{n}}\\\\=\sqrt{\dfrac{(0.59)(1-0.59)}{105}}\\\\=\sqrt{0.00230381}\\\\=0.047998015832\approx0.048$

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2 years ago

Please show your work.

levacccp [35]

The amount of money you have is $ 20864.521

<h3>Solution:</h3>

Given that you invested $15,000 dollars for 11 years at 3% annual interest compounded continuously.

To find: total amount of money

The compound interest formula for compounded continously is given as:

$A = p e^{rt}$

Where "p" is the principal

"r" is the rate of interest

"t" is the number of years

Here in this problem, p = 15000

t = 11 years

$r = 3 \% = \frac{3}{100} = 0.03$

Substituting the values in formula we get,

$A = 15000e^{0.03 \times 11}\\\\A = 15000e^{0.33}\\\\A = 15000 \times 1.390968\\\\A = 20864.521$

Thus the amount of money you have is $ 20864.521

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2 years ago