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Katarina [22]
1 year ago
11

What is Q3 for this data set?

Mathematics
2 answers:
Kisachek [45]1 year ago
8 0

The same as last time

Step-by-step explanation:

andrew-mc [135]1 year ago
3 0

Answer:

Step-by-step explanation:

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ASAP HELP ANSWER ALL THESE AND I WILL GIVE THE BRAINLEST
alexandr1967 [171]
The second question is number 3 for the polygon translation.
Question 3 is 2 units right and four units down.
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2 years ago
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Explain why the "+ C" is not needed in the antiderivative when evaluating a definite integral.
Aliun [14]

The reason the "+ C" is not needed in the antiderivative when evaluating a definite integral is; The C's cancel each other out as desired.

<h3>How to represent Integrals?</h3>

Let us say we want to estimate the definite integral;

I = \int\limits^a_b {f'(x)} \, dx

Now, for any C, f(x) + C is an antiderivative of f′(x).

From fundamental theorem of Calculus, we can say that;

I = \int\limits^a_b {f'(x)} \, dx  = \phi(a) - \phi(b)

where Ф(x) is any antiderivative of f'(x). Thus, Ф(x) = f(x) + C would not work because the C's will cancel each other.

Read more about Integrals at; brainly.com/question/22008756

#SPJ1

8 0
1 year ago
Alyssa plans to borrow $3,180 at 6.5% for 3.5 years . Find the amount of simple interest she should expect to pay.
irga5000 [103]

Answer:

784.16

Step-by-step explanation:

use the formula for simple interest =

P(1+r)^t

so

3180(1.065)^3.5 - 3180

3 0
2 years ago
Use linear approximation to approximate √25.3 as follows.
Sophie [7]

The idea is to use the tangent line to f(x)=\sqrt x at x=25 in order to approximate f(25.3)=\sqrt{25.3}.

We have

f(x)=\sqrt x\implies f(25)=\sqrt{25}=5

f'(x)=\dfrac1{2\sqrt x}\implies f'(25)=\dfrac1{10}

so the linear approximation to f(x) is

L(x)=f(5)+f'(5)(x-5)=5+\dfrac{x-5}{10}=\dfrac x{10}+\dfrac92

Hence m=\frac1{10} and b=\frac92.

Then

f(25.3)\approx L(25.3)=\dfrac{25.3}{10}+\dfrac92=\boxed{7.03}

4 0
3 years ago
College Calculus - hyperbolic functions (see attachment)
morpeh [17]

Answer:

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

Step-by-step explanation:

Using the fundamental theorem of calculus

Taking the derivative of the integral gives back the function

Since the lower limit is a constant when we take the derivative it is zero

d/dx \int\limits^x_4 {g(t)} \, dt  = g(x)

g(t) = sinh^-1 ( ln(7t^6 +3) / sqrt( 8+cot( t^( 3+t))))

Replacing t with x

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

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3 years ago
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