Ask question

Ask question

All categories

3 years ago

10

Use the formula d = rt to find the distance d a long distance runner can run at a rate of 9 1/2 miles per hour for time t or 1 3

/4 hours

1 answer:

LiRa [457]3 years ago

7 0

D = (9 1/2) (1 3/4) D = 11 7/8 miles

You might be interested in

There are 5 students in class. each will be assigned a grade of a, b or

antiseptic1488 [7]

There could be five in each class.

8 0

3 years ago

A farmer is building a grain silo for storage. he estimates that will need 256 cubic yards of storage. the grain silo will be sh

Vlad1618 [11]

Check the picture below.

keeping in mind that a cube is just a rectangular prism with all equal sides.

7 0

3 years ago

Find the equations of the tangent lines to x2+y2=1 at x=0, x=1 and x=35.

Ivanshal [37]

Assuming the equation is x^2 + y^2 = 1, then that's a circle, with radius 1, centered on the origin [0,0].

So there are two tangents at x = 0. They are y = 1, and y = -1 (horizontal lines).

There is one tangent at x = 1. It is x = 1 (a vertical line).

There is no tangent at x = 35, because the original equation has no solution at x = 35.

4 0

3 years ago

You are given f(0) = 1 and g(0) = -2 and g(1) = 3. What is <br> g ∘ f ( 0 ) <br> equal to?

Sergeu [11.5K]

Answer:

<u><em>g∘f (0) = 1</em></u>

Explanation:

The <em>composition</em> of the <em>functions</em> f and g represented by g ∘ f ( 0 ) means that g is applied to f(0), i.e f(0) is the input to the function g.

Since f(0) = 1, you are going fo find g(1):

$\( g\circ f(x)=g(f(x)) \)\\\\\( g\circ f(0)=g(f(0)) \)\\\\\( g\circ f(0)=g(1) \)=3$

4 0

3 years ago

manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin

alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) $nCr q^{r} p^{n-r}$

$nCr = \frac{n!}{(n-r)!r!}$

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = $20C18 * 0.97^{18} * 0.03^{20-18}$

P(X=18) = $20C18 * 0.97^{18} * 0.03^{2}$

P(X=18) = 0.0988

P(X=19) = $20C19 * 0.97^{19} * 0.03^{20-19}$

P(X=19) = $20C19 * 0.97^{19} * 0.03^{1}$

P(X=19) = 0.3364

P(X=20) = $20C20 * 0.97^{20} * 0.03^{20-20}$

P(X=20) = $20C20 * 0.97^{20} * 0.03^{0}$

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0

3 years ago