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Burka [1]
3 years ago
9

a salesperson receives a 2.5% commission on sales. what commission does the salesperson receive for $8000 in sales?

Mathematics
1 answer:
Gelneren [198K]3 years ago
7 0
The sales person receives a $200 sales commission. To get the answer, you would convert the percentage to a decimal, in this case... 2.5%, would become 0.025. You would then multiply 0.025•8000 to get your answer of $200. Which means in total, the salesperson would receive $8200.
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A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances
wariber [46]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to compare two compounds, designed to reduce braking distance, used in tire manufacturing to prove if the braking distance of SUV's equipped with tires made with compound 1 is shorter than the braking distance of SUV's equipped with tires made with compound 2.

So you have 2 independent populations, SUV's equipped with tires made using compound 1 and SUV's equipped with tires made using compound 2.

Two samples of 81 braking tests are made and the braking distance was measured each time, the study variables are determined as:

X₁: Braking distance of an SUV equipped with tires made with compound one.

Its sample mean is X[bar]₁= 69 feet

And the Standard deviation S₁= 10.4 feet

X₂: Braking distance of an SUV equipped with tires made with compound two.

Its sample mean is X[bar]₂= 71 feet

And the Standard deviation S₂= 7.6 feet

We don't have any information on the distribution of the study variables, nor the sample data to test it, but since both sample sizes are large enough n₁ and n₂ ≥ 30 we can apply the central limit theorem and approximate the distribution of both variables sample means to normal.

The researcher's hypothesis, as mentioned before, is that the braking distance using compound one is less than the distance obtained using compound 2, symbolically: μ₁ < μ₂

The statistical hypotheses are:

H₀: μ₁ ≥ μ₂

H₁: μ₁ < μ₂

α: 0.05

The statistic to use to compare these two populations is a pooled Z test

Z= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } }

Z ≈ N(0;1)

Z_{H_0}= \frac{69-71-0}{\sqrt{\frac{108.16}{81} +\frac{57.76}{81} } }= -1.397

The rejection region if this hypothesis test is one-tailed to the right, so you'll reject the null hypothesis to small values of the statistic. The critical value for this test is:

Z_{\alpha  } = Z_{0.05}= -1.648

Decision rule:

If Z_{H_0} > -1.648 , then you do not reject the null hypothesis.

If Z_{H_0} ≤ -1.648 , then you reject the null hypothesis.

Since the statistic value is greater than the critical value, the decision is to not reject the null hypothesis.

At a 5% significance level, you can conclude that the average braking distance of SUV's equipped with tires manufactured used compound 1 is greater than the average braking distance of SUV's equipped with tires manufactured used compound 2.

I hope you have a SUPER day!

4 0
3 years ago
Is 0.0575 greater than 5.75
Harrizon [31]

no. its not round it to 0 and 5 or 6

6 0
3 years ago
Read 2 more answers
Help please have 15 minutes
aalyn [17]
It would be the last one. Because 3×10 is 30 and 30 to the seventh power would be 30,000,000
8 0
3 years ago
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Home work.......harrrrrrrrry​
mart [117]

Answer:

21 letters.

Step-by-step explanation:

So, what you need to find here is how many letters precede the letter V. You could count the letters, but since V is near to the end of the alphabet, faster way would be to count the letters from behind. We know that the ending streak of the alphabet is ...v, w, x, y, z, and we also know that the english alphabet has 26 letters. So if we count from behind we find that V is fifth letter from behind ( z is 26th, y is 25th, x is 24th, w is 23rd and v is 22nd). Finally, since V is 22nd letter, that means that it is preceded by 21 letter.

7 0
3 years ago
Help me with my question I don’t get it
kotegsom [21]

Answer:

7/9 to a

.62 to b

10/9 to c

4 0
3 years ago
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