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3 years ago

Please help

Chemistry

2 answers:

lara [203]3 years ago

7 0

Explanation:

Ideal gas law states that the product of the pressure and the volume of one gram molecule of an ideal gas is equal to the product of the absolute temperature of the gas and the universal gas constant.

Mathematically, PV = nRT

where, P = pressure

V = volume

n = number of moles

R = gas constant

T = absolute temperature

A gas behaves ideally at high temperature and low pressure because when pressure is low and temperature is high then there will be more number of collisions between the gas particles. As a result, kinetic energy of molecules will increase hence, molecule's size will become less significant as compared to the empty space between them.

Therefore, conditions for which the ideal gas law will be most accurate are as follows.

high temperatures
low pressures

kotegsom [21]3 years ago

4 0

High temp and low pressure

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A 12.0 g sample of a metal is heated to 90.0 ◦C. It is then dropped into 25.0 g of water. The temperature of the water rises fro

deff fn [24]

Answer:

The specific heat of the metal is 0.34 J/g°C

Explanation:

Step 1: Data given

Mass of the metal = 12.0 grams

Mass of the water = 25.0 grams

Initial temperature of the metal = 90.0 °C

Initial temperature of the water = 22.5 °C

Final temperature = 25 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of the metal

Qlost = Qgained

Q = m*c*ΔT

Qmetal = -Qwater

m(metal) *c(metal)* ΔT(metal) = -m(water) * c(water) *ΔT(water)

⇒ with mass of metal = 12.0 grams

⇒ with c(metal) = TO BE DETERMINED

⇒ with ΔT(metal) = T2 - T1 = 25.0°C - 90.0 °C = -65.0 °C

⇒ with mass of water = 25.0 grams

⇒ with c(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.0 - 22.5 °C = 2.5 °C

12.0 * c(metal) * -65.0 °C = -25.0g * 4.184 J/g°C * 2.5°C

-780.0 * c(metal) = -2615 ( 2.6*10^3 with sig figs)

c(metal) = 0.335 (=0.34 with sig figs)

The specific heat of the metal is 0.34 J/g°C

3 0

3 years ago

the temperature of a balloon rises from 275 degrees k to 395 degrees k, what would the ending volume be if it started at 5 L

Airida [17]

<h3>Answer:</h3>

7.182K

<h3>Explanation:</h3>

From the question we are given;

Initial temperature, T1 = 275 K
Final temperature, T2 = 395 K
Initial volume, V1 = 5 L

We are required to calculate the final volume, V2

Charles's law is the law that relates the volume of a gas and its temperature.
It states that the volume of a fixed mass of a gas and its absolute temperature are directly proportional at a constant pressure.
Therefore;

$\frac{V1}{T1}=\frac{V2}{T2}$

To calculate, V2 we rearrange the formula;

$V2=\frac{V1T2}{T1}$

$V2=\frac{(5L)(395K)}{275}$

$V2=7.182K$

Therefore, the ending volume will be 7.182K

8 0

4 years ago

CARDS

valina [46]

Answer:d

Explanation:

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3 years ago

Which is a polar molecule?

Sloan [31]

A polar molecule is when the arrangement of the atoms in molecules are unequal where one end of the molecule has a positive charge while the other end has a negative charge. Examples of a polar molecule are water, ammonia, hydrogen sulfide and sulfur dioxide. The opposite is called a nonpolar molecule.

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4 years ago

Which of the following is an example of commensalism?

Contact [7]

Answer: A tick on a deer

Explanation:

because commensalism is a type of symbiotic relationship in which one species benefits, while the other species is neither harmed nor helped

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7 0

3 years ago